Answer:
The answer to that question would be A
Explanation:
Answer:
30 μmol/L
Explanation:
<em>A chemist prepares a solution of barium chloride by measuring out 8.9 μmol of barium chloride into a 300mL volumetric flask and filling the flask to the mark with water.
</em>
<em>
Calculate the concentration in μmol L of the chemist's barium chloride solution. Round your answer to 2 significant digits.</em>
<em />
The chemist has 8.9 μmol of solute (barium chloride) and he adds water until the mark of 300 mL in the container, which is the volume of the solution. We will need the conversion factor 1 L = 1000 mL. The concentration of barium chloride in μmol/L is:
We have that the name (not chemical symbol) of the main group element in period 5 and group 3A is
Metalloid boron (B)
From the Question we are told that
The element belongs to
Period 5 and group 3A
Generally
Group 3A of the periodic table includes the metalloid boron (B), aluminum (Al), indium (In), and thallium (Tl) gallium (Ga),
Period 5 is possessed by the metalloid boron (B) of the Group 3A
For more information on this visit
brainly.com/question/13025901?referrer=searchResults
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
They are different elements. However, most of their chemical properties are similar, because of the similar numbers of electrons in their valence shells. Their physical properties differ because of the mass contained in the atoms of <span>each element.</span>
Answer:
The amount of heat released is 11.3 KJ
Explanation:
H20(g) -> H20(l) + heat
This reaction is changing state from gaseous to liquid without changing the temperature. This heat is know as Latent heat. It is the energy required for a phase change.
Heat released by 5 g of water vapor (Q) = M × L
where M = mass of vapor
L= latent heat
Latent heat can be divide into 2
- Latent heat of fusion
- Latent heat of vaporization
Since we are change the gaseous state to liquid, we will be working with Latent heat of vaporization which has a value of 22.6 x 10 ∧5 J/kg
(Q) = M × L
= 0.005 x 22.6 x 10 ∧5
= 11300 J
= 11.3 KJ
