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Kobotan [32]
3 years ago
13

Calculate the internal energy of 2 moles of argon gas (assuming ideal behavior) at 298 K. Suggest two ways to increase its inter

nal energy by 10 J.

Chemistry
1 answer:
Dominik [7]3 years ago
5 0
I hope this helps you.

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What is the last energy level of N? Mg?
Alexandra [31]

Answer:

2

3

Explanation:

To infer the last energy of the given atoms, we need to write their electronic configuration:

For N = 1S² 2S² 2P³

     Mg  = 1S² 2S² 2P⁶ 3S²  

The energy levels are usually designated as;

   n = 1

   n = 2

   n = 3

   n =4

For N, the last energy level is 2

     Mg, the last energy level is 3

We can also determine this number by the periods the atoms can be found.

3 0
3 years ago
If the internal energy of a system increases but there is no change in temperature, then the system's energy is increasing.
777dan777 [17]

Answer:

kintic

Explanation:

4 0
4 years ago
Read 2 more answers
Which of the following changes depending on the strength of the gravity field it is in?
jek_recluse [69]
I believe it’s C.) Mass. Hope I’m right.
5 0
3 years ago
Five gases combined in a gas cylinder have the following partial pressures: 3.00 atm (N2), 1.80 atm (O2), 0.29 atm (Ar), 0.18 at
lisov135 [29]

This can be solved using Dalton's Law of Partial pressures. This law states that the total pressure exerted by a gas mixture is equal to the sum of the partial pressure of each gas in the mixture as if it exist alone in a container. In order to solve, we need the partial pressures of the gases given. Calculations are as follows:<span>


<span>P = 3.00 atm + 1.80 atm + 0.29 atm + 0.18 atm + 0.10 atm</span></span>

<span><span>P = 5.37 atm</span></span>

5 0
3 years ago
Read 2 more answers
A solution is made by mixing 33.0 ml of ethanol, C2H6O and 67.0 ml of water. Assuming ideal behavior, what is the vapor pressure
ivann1987 [24]
Grams ethanol = 33 ml times .789 gms/ml = 26.037 gms 

<span>Moles ethanol = 26.037 gms / 46 gms/mole = .57 moles </span>

<span>Moles water = 67 ml or 67 grams/18 gms/mole = 3.22 moles </span>

<span>total moles = .57 + 3.72 = 4.29 moles </span>

<span>Mole fraction ethanol = .57 moles ethanol / 4.29 moles total = 0.13</span>

<span>Moles fraction water = 3.72 moles water / 4.29 moles total = 0.87</span>

<span>Partial pressure of ethanol = mole fraction ethanol (.13) _ times VP ethanol 43.9 torr) = 5.707 torr </span>

<span>partial pressure water = mole fraction water .87) times VP water (l7.5 torr) = 15.23 torr </span>

<span>Total vapor pressure over solution = 5.71 torr + 15.23 torr = 20.94 torr</span>
7 0
3 years ago
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