Answer: 15.433704
Use the periodic table to check the atomic mass, this is the number of grams per mole → 1 mole of Aluminum is 26.982 g
Answer: No
Explanation: For it to be a divergent boundary, the arrows would have to be pointing in opposite directions. (one points left, one points right).
In this item, we are simply to find the ions that may bond and are able to form a formula unit. We are also instructed to give out their name. There are numerous possible combinations of ions to form a compound. Some answers are given in the list below.
1. Na⁺ , Cl⁻ , NaCl ---> sodium chloride (this is most commonly known as table salt)
2. C⁴⁺ , O²⁻ , CO₂ ---> carbon dioxide
3. Al³+ , Cl⁻ , AlCl₃ ----> aluminum chloride
4. Ca²⁺ , Cl⁻ , CaCl₂ ---> calcium chloride
5. Li⁺ , Br⁻ , LiBr ---> lithium bromide
6. Mg³⁺ , O²⁻ , Mg₂O₃ ----> magnesium oxide
7. K⁺ , I⁻ , KI ---> potassium iodide
8. H⁺ , Cl⁻ , HCl --> hydrogen chloride
9. H⁺ , Br⁻ , HBr ----> hydrogen bromide
10. Na⁺ , Br⁻ , NaBr ---> sodium bromide
Answer : The final pressure will be, 666.2 mmHg
Explanation :
Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.
or,
where,
= initial pressure = 790 mmHg
= final pressure = ?
= initial volume = 101.2 mL
= final volume = 120 mL
Now put all the given values in the above equation, we get:
Therefore, the final pressure will be, 666.2 mmHg
Let empirical formula for hydrocarbon is CxHy
it will undergo combustion as
CxHy + (x + y/4) O2 ---> xCO2 + (y/2 )H2O
Given that mass of CO2 produced = 9.69 g
So moles of CO2 produced = 9.69 / 44 = 0.22 moles
So moles of carbon present = 0.22 moles
mass of H2O produced = 4.96 g
Moles of H2O produced = mass / molar mass = 4.96 / 18 = 0.28 moles
So moles of H present = 2 X 0.28 = 0.56 moles
Let us divided the moles of each with lowest value of moles
Moles of Carbon = 0.22 / 0.22 = 1 moles
moles of H = 0.56 / 0.22 = 2.55
Multiplying with two to get whole number
the ratio of carbon and hydrogen will be : C:H = 2:5
empirical formula : C2H5
