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Rus_ich [418]
3 years ago
8

Help please help!!!!!!!!

Physics
1 answer:
Sidana [21]3 years ago
6 0

1. Electron

2. Neutron

3. Nucleus

4. Atom

5. Molecule

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A person travels by car from one city to another with different constant speeds between pair of cities. She drives for 36 min at
Softa [21]

 Change minutes to hrs, divide by 60:
30 min = .50 hrs
45 min = .75 hrs
12 min = .20 hrs
----------------
total + 1.45 hrs, total travel time
:

let a = average speed for the trip
:
Write a dist equation, dist = speed * time
:
80(.5) + 100(.20) + 40(.75) = 1.45a
40 + 20 + 30 = 1.45a
90 = 1.45a
a =
a = 62.069 km/h, for the entire trip
and
90 km is the total distance 

3 0
3 years ago
The standard normal curve is not symmetrical. <br> a. True<br> b. False
FrozenT [24]

Answer;

The above statement is false

Explanation;

Symmetrical distribution, commonly known as symmetric distribution or normal distribution, is typically unimodal, meaning it shows only one peak in graph form.

It is a type of distribution where the left side of the distribution mirrors the right side. By definition, a symmetric distribution is never a skewed distribution.

All normal distributions are symmetric and have bell-shaped density curves with a single peak.

7 0
3 years ago
Read 2 more answers
Which best describes most covalent compounds?<br> O soft<br> O brittle<br> 3<br> O cold<br> O warm
LUCKY_DIMON [66]

Answer: Brittle

Explanation:

took the test and I chose Soft, Soft is the wrong answer don't choose it. The CORRECT ANSWER IS BRITTLE

7 0
4 years ago
What is the speed of light in air ?<br><img src="https://tex.z-dn.net/?f=%20%5C%5C%20" id="TexFormula1" title=" \\ " alt=" \\ "
hichkok12 [17]

Answer:

the speed of light in air is about 299,000,000 and 3×10⁸ m/s

4 0
2 years ago
Read 2 more answers
An 8.00- W resistor is dissipating 100 watts. What are the current through it and the difference of potential across it?
hjlf

Answer:

I= 3.5 amps

Explanation:

Step one:

given data

rating of resistor R= 8 ohms

power P= 100W

Required

The current I

Step two

Yet this power is also given by

P = I^2R

make I subject of the formula we have

I= \sqrt{\frac{P}{R} }

substitute

I= \sqrt{\frac{100}{8} }\\\\I=\sqrt{12.5}\\\\I= 3.5 amps

8 0
3 years ago
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