Answer:
another ball velocity = 3.92 m/s and with 30° clockwise from initial direction
Explanation:
given data
mass m1 = 0.165 kg
mass m2 = 0.155 kg
before collision velocity v1 = 5.8 m/s
before collision velocity v2 = 0
angle = 35.0° from initial direction
after collision 1st ball velocity v3 = 3.2 m/s
to find out
after collision another ball velocity v4
solution
we consider here ball move in x axis and after collision 1st ball move upside of x axis with angle 35 degree and other ball move downside with x axis with angle θ
so from conservation of momentum we say
m1v1 = m1v3cos35 + m2v4cosθ with x axis .............1
m1v3sin35 = m2v4sinθ with y axis .............2
so from 1 equation
0.165 × 5.8 = 0.165(3.2)cos35 + 0.155(v4)cosθ
v4 cosθ = 3.38 .................3
form 2 equation
0.165(3.2)sin35 = 0.155(v4)sinθ
v4 sinθ = 1.95 ......................4
so magnitude of another ball velocity is square and adding equation 3 and 4
another ball velocity = √(3.39²+1.96²)
another ball velocity = 3.92 m/s
and direction is tanθ = 1.96/3.39
θ = 30° clockwise from initial direction
