Answer:
all of the above
Explanation:
i got the answer right on cK-12
This problem is providing the chemical reaction whereby barium nitride reacts with water to produce barium hydroxide and ammonia, so the number of moles of barium nitride are required in order to produce 8.3 moles of ammonia. It asks for us to evaluate the student's setup, so we conclude the answer is C. "1 mol of NH3 should be replaced with 2 mol of NH3", according to:
<h3>Mole ratios:</h3>
In chemistry, stoichiometric calculations are used to figure out the moles or mass of a substance, given information about another one in the reaction. In this case, for the given chemical equation:

We evidence a 1:2 mole ratio of barium nitride to ammonia, for that reason, the student's setup:

Is incorrect, because the ammonia must be accompanied by a 2 rather than the 1 it is given there:

Thereby, the correct answer is C. "1 mol of NH3 should be replaced with 2 mol of NH3"
Learn more about mole ratios: brainly.com/question/15288923
An atom of vanadium
(V) has 23 electrons.
Given :
A vanadium (V) atom with 23 protons and has a net charge of 0.
To find:
The number of electrons in a vanadium atom
Solution:
Number of protons in vanadium atom = 23
The 0 net charge on the atom indicates that the atom has an equal number of protons and electrons which makes it a neutral atom.
Number of electrons in vanadium atom = Number of protons in vanadium atom = 23
An atom of vanadium
(V) has 23 electrons.
Learn more about subatomic particles here:
brainly.com/question/7221719?referrer=searchResults
brainly.com/question/489853?referrer=searchResults
Answer is: 315,29 grams of copper ore.
m(<span>chalcopyrite) = ?
</span>ω(CuFeS₂) = 55,0 % = 0,55.
<span>m(Cu) = 60,0 g.
mass percentage of copper in </span>CuFeS₂:
ω(Cu) = Ar(Cu) ÷ Mr(CuFeS₂).
ω(Cu) = 63,55 ÷ 183,4.
ω(Cu) = 0,346 = 34,6 %.
mass percentage of copper in chalcopyrite:
ω(Cu) : ω₁(Cu) = 100% : ω(CuFeS₂).
ω₁(Cu) = 19,03 % = 0,1903.
m(chalcopyrite) = 60,0 g ÷ 0,1903.
m(chalcopyrite) = 315,29 g.