Which statement is true about the products of two reactants that combine chemically?

(Brainliest) Please Help! Please do not give me a random, gibberish answer or I will report you and give you a low rating theref

nataly862011 [7]

Answer:

3.10g

Explanation:

Please see the attached picture for the full solution.

3 0

3 years ago

What volumes of 0.200 M HCOOH and 2.00 M NaOH would make 500. mL of a buffer with the same pH as one made from 475 mL of 0.200 M

Fed [463]

36 ml of NaOh and 464 ml of HCOOH would be enough to form 500 ml of a buffer with the same pH as the buffer made with benzoic acid and NaOH.

What is benzoic acid found in?

Some natural sources of benzoic acid include: Fruits: Apricots, prunes, berries, cranberries, peaches, kiwi, bananas, watermelon, pineapple, oranges.
Spices: Cinnamon, cloves, allspice, cayenne pepper, mustard seeds, thyme, turmeric, coriander.

Calculate the amount of moles in NaOH and benzoic acid. This calculation is done by multiplying molarity by volume.

Amount of moles of NaOH -2 × 0.025 = 0.05 mol

Amount of moles of benzoic acid 2 × 0.475 = 0.095 mol

In this case, we can calculate the pH produced by the buffer of these two reagents, as follows

$pH = pKa + log\frac{base}{acid}$

$4.2 + log\frac{0.05}{0.045} = 4.245$

We must repeat this calculation, with the values shown for HCOOH and NaOH. In this case, we can calculate as follows

$pH = pKa + log\frac{base}{acid}$

$4.245 = 3.75 + log\frac{base}{acid}$

$log\frac{base}{acid} = 0.5$

$\frac{base}{acid} = 3.162$

Now we must solve the equation above. This will be done using the following values

$\frac{2(0.5 - x)}{0.2x - 2(0.5 - x)} = 0.464 L$

With these values, we can calculate the volumes of NaOH and HCOOH needed to make the buffer.

NaOH volume

( 0.5 - 0.464)L

0.036L .................... 36ml

HCOOH volume

500 - 36 = 464mL

Learn more about benzoic acid

brainly.com/question/24052816

#SPJ4

3 0

2 years ago

A student uses 0. 0821 LĂ˘â‚¬Ë atm/mol Ă˘â‚¬Ë K as the value of the gas constant. What is most likely true about the variables i

xz_007 [3.2K]

The variables in the ideal gas constant has V as the unit of liters and T has the unit of Kelvin. Thus, option C is correct.

The gas constant in an ideal gas equation has been the value of the energy absorbed by 1 mole of an ideal gas at standard temperature and pressure.

The value of R has been dependent on the units of volume, temperature and pressure of the ideal gas.

The given value of R has been 0.0821 L.atm/mol.K

The unit in gas constant has been L (Liter) for volume (V).

The unit of pressure (P) has been atm.

The unit of temperature (T) has been Kelvin (K).

Thus the gas law constant used by student has V has the unit of liters and T has the unit of Kelvin. Thus, option C is correct.

For more information about the gas constant, refer to the link:

brainly.com/question/24814070

6 0

3 years ago

The spectrophotometer really measures the percent of light that is transmitted through the solution. The instrument then convert

Fantom [35]

Hey there!:

absorbance = log 100 - log Transmitance

absorbace = 0.85

log 100 = 2

- log transmitance = absorbace / log 100

0.85 / 2= 0.425

transmitance = 10 ^ ( - 0.425 )

transmitance = 0.376

4 0

3 years ago

The amount of energy required to raise the temperature of a swimming pool depends on the mass of water present.

cluponka [151]

True. Refer to the heat equation of water

3 0

3 years ago