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AlexFokin [52]
3 years ago
9

3. Suppose that a block is pulled 16 meters across a floor. What amount of work is done if the force used to drag the block is 2

2 N?
A. 3303
B. 200
C.3523
D. 2203
Physics
1 answer:
Nadusha1986 [10]3 years ago
7 0

Explanation:

Work is the product of force and distance.

W = F×d

W = (22 N) × (16 m)

W = 352 J

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Calculate the distance traveled by a projectile as a function of launch angle. Compare the distances for two projectiles launche
DaniilM [7]

Answer:

R = x_{max} = \frac{v^2\sin(2\theta)}{g}\\\frac{R_1}{R_2} = \frac{\sin(2\theta_1}{\sin(2\theta_2}

Explanation:

Using kinematics equations:

\Delta x = v_{0x}t\\\Delta y = -\frac{1}{2}gt^2+v_{0y}t

Use \Delta y = 0 due to condition of distance traveled.

Solving second equation for time, there are two solutions. t=0 and

t=\frac{2v_{0y}}{g}

Use the expression in the first equation to have

R = \frac{2v^2 \cos\theta\sin\theta}{g}

Using trigonometric identities, you have the answer of the distance.

By doing the ratio for two different angles, you have the second answer. Due to sine function properties, the distances can be the same to complementary angles. Example, for 20° and 70°, the distance is the same.

5 0
3 years ago
One uniform ladder of mass 30 kg and 10 m long rests against a frictionless vertical wall and makes an angle of 60o with the flo
yuradex [85]

Answer:

   μ = 0.37

Explanation:

For this exercise we must use the translational and rotational equilibrium equations.

We set our reference system at the highest point of the ladder where it touches the vertical wall. We assume that counterclockwise rotation is positive

let's write the rotational equilibrium

           W₁  x/2 + W₂ x₂ - fr y = 0

where W₁ is the weight of the mass ladder m₁ = 30kg, W₂ is the weight of the man 700 N, let's use trigonometry to find the distances

             cos 60 = x / L

where L is the length of the ladder

              x = L cos 60

            sin 60 = y / L

           y = L sin60

the horizontal distance of man is

            cos 60 = x2 / 7.0

            x2 = 7 cos 60

we substitute

         m₁ g L cos 60/2 + W₂ 7 cos 60 - fr L sin60 = 0

         fr = (m1 g L cos 60/2 + W2 7 cos 60) / L sin 60

let's calculate

         fr = (30 9.8 10 cos 60 2 + 700 7 cos 60) / (10 sin 60)

         fr = (735 + 2450) / 8.66

         fr = 367.78 N

the friction force has the expression

         fr = μ N

write the translational equilibrium equation

         N - W₁ -W₂ = 0

         N = m₁ g + W₂

         N = 30 9.8 + 700

         N = 994 N

we clear the friction force from the eucacion

        μ = fr / N

        μ = 367.78 / 994

        μ = 0.37

3 0
3 years ago
1.
drek231 [11]

Answer:

2500m

Explanation:

given,

initial velocity(u) = 5m/s

final velocity (v) = 0 m/s ( as he/she stopped riding after 1000 secs)

time = 1000 secs

distance(s)=?

now,

s=( u+v ) ×t /2

=(5+0)×1000/2

=2500 m

hence, he /she travels 2500m far

8 0
3 years ago
What is magnetic resonance???​
Lyrx [107]

Answer:

procedure in which radio waves and a powerful magnet linked to a computer

Explanation:

Listen to pronunciation. (mag-NEH-tik REH-zuh-nunts IH-muh-jing) A procedure in which radio waves and a powerful magnet linked to a computer are used to create detailed pictures of areas inside the body. These pictures can show the difference between normal and diseased tissue.

5 0
3 years ago
Read 2 more answers
What is the system of blood and blood vessels and the heart
Karo-lina-s [1.5K]
Answer:circulatory system 
8 0
3 years ago
Read 2 more answers
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