Ask question

Ask question

All categories

4 years ago

9

3. Suppose that a block is pulled 16 meters across a floor. What amount of work is done if the force used to drag the block is 2

2 N?
A. 3303
B. 200
C.3523
D. 2203

1 answer:

Nadusha1986 [10]4 years ago

7 0

Explanation:

Work is the product of force and distance.

W = F×d

W = (22 N) × (16 m)

W = 352 J

You might be interested in

Un tubo cilíndrico de acero tiene 2.4 cm3 de volumen a -20°C. ¿Cuál será su volumen con una temperatura final de 47C ? Y ¿ Cuál

vaieri [72.5K]

i searched this in googl.e, and there was one website, so i clicked it, and umm it was very disgusting ,,,

4 0

3 years ago

Tju [1.3M]

Micah knows that a car had a change in velocity of 15 m/s.To determine acceleration ,Micah also needs the TIME of the total trip in seconds.

8 0

3 years ago

Read 2 more answers

A rocket is fired with an initial VELOCITY OF 100m/s at an angle of 55° above the horizontal, It explodes On the mountain Side 1

GuDViN [60]

Answer

688.32m and 277.44m

Explanation :

⠀

$\large{\maltese{\textsf{\underline{To find :-}}}}$

The X and Y coordinates of the rocket relative of firing

⠀

⠀

$\large{\maltese{\textsf{\underline{Given :-}}}} \\ \\ \sf velocity (v_i) = 100m{s}^{-1} \\ \sf angle ({\theta}_{1}) = 55.0{\degree} \\ \sf time (t) = 12s$

⠀

⠀

$\Large{\maltese{\textsf{\underline{\underline{Step by Step Solution:-}}}}}$

⠀

⠀

<u>The</u><u> </u><u>horizontal</u><u> </u><u>range</u><u> </u><u>of</u><u> </u><u>projectile</u><u> </u><u>at</u><u> </u><u>x</u><u>.</u><u> </u>

⠀

$\sf \large{x = v_{xi}} \times t \\ \\ \sf \large{x = v_i \times \cos {\theta}_{i} \times t}$

⠀

⠀

$\large\textsf{\underline{Now substituting the required values}}$

⠀

⠀

$\sf x = 300 \times \cos 55{\degree} \times 12 \\ \\ \sf x = 100 \times 0.5756 \times 12 \\ \\ {\underline{\boxed{\bold{ x = 688.32m}}}}$

⠀

⠀

The vertical position of projectile at y.

⠀

⠀

$\sf \large y = v_{yi} \times t - (\frac{1}{2} \times g \times {t}^{2}) \\ \\ \sf \large y = v_i \times \cos \theta \times t - \frac{1}{2} g {t}^{2}$

⠀

⠀

$\textsf{ \large {\underline{Now substituting the required values}} }$

⠀

⠀

$\sf y = 100 \times \cos55{ \degree} \times 12 - \frac{1}{2} \times 9.80 \times {12}^{2} \\ \\ \sf y = 100 \times 0.8192 \times 12 - 0.5 \times 9.8 \times 144 \\ \\ \sf y = 983.04 - 705.6 \\ \\ \underline{ \boxed{ \bold{y = 277.44m}}}$

⠀

⠀

⠀

<h3><u>Henceforth</u><u>,</u><u> </u><u>the</u><u> </u><u>distance</u><u> </u><u>at</u><u> </u><u>horizon</u><u> </u><u>is</u><u> </u><u>6</u><u>8</u><u>8</u><u>.</u><u>3</u><u>2</u><u>m</u><u> </u><u>and</u><u> </u><u>at</u><u> </u><u>vertical</u><u> </u><u>is</u><u> </u><u>2</u><u>7</u><u>7</u><u>.</u><u>4</u><u>4</u><u>m</u><u>.</u></h3>

8 0

2 years ago

Increasing the concentration of greenhouse gases in Earth's atmosphere decreases the transparency of the atmosphere to infrared

Artist 52 [7]

Answer:

Decrease the transparency of the atmosphere

Explanation:

Different gases have characteristic absorption bands, so-called greenhouse gases have very high bands in the infrared region and small bands in the region of visible light.

When the radiation arrives to pass the greenhouse gases (CO²) and affects the earth's surface after several processes, the earth emits radiation in the infrared region, but this is absorbed by the gases, creating a net heating, since that the transparency of the atmosphere is DECREASE for infrared radiation

Reviewing the correct answers is: Decrease the transparency of the atmosphere

5 0

3 years ago

Kevin is standing outside a railway station. He can know whether a train is approaching the station or departing from the sound

aivan3 [116]

It looks like Doppler effect. Sound waves passing through a big way until they get to your ears. We got the highest frequency when we receive it, while it goes it remains the same and when it goes down we receive lower frequency.

3 0

3 years ago