Ask question

Ask question

All categories

3 years ago

9

3. Suppose that a block is pulled 16 meters across a floor. What amount of work is done if the force used to drag the block is 2

2 N?
A. 3303
B. 200
C.3523
D. 2203

1 answer:

Nadusha1986 [10]3 years ago

7 0

Explanation:

Work is the product of force and distance.

W = F×d

W = (22 N) × (16 m)

W = 352 J

You might be interested in

PLEASE ANSWER 50 POINTS SPENT I'LL GIVE BRAINLIEST TO THE PERSON WHO ANSWERS ALL! (or most)

Afina-wow [57]

Answer:

1) The matter absorbs or reflects the light

2) Lens

3) <u><em>Concave</em></u>- curves inwards. Diverges light

b.<u><em>Convex</em></u>- curves outward. Converges light

4) The image is real if the distance of the object from the lens is greater than the focal length and virtual if it is less than the focal length

5) Lens and, for convex lenses, on the distance between the lens and the object.

6) Index of refraction?

Explanation:

I hope this helped you, sorry if anything is wrong

6 0

3 years ago

bagirrra123 [75]

Explanation:

The reading on the scale is

W = m(g + a)

= (77 kg)(9.8 m/s^2 + 2 m/s^2)

= 908.6 N

7 0

3 years ago

(a) What is the minimum width of a single slit (in multiples of λ ) that will produce a first minimum for a wavelength λ ? (b) W

Kitty [74]

Answer:

The minimum value of width for first minima is λ

The minimum value of width for 50 minima is 50λ

The minimum value of width for 1000 minima is 1000λ

Explanation:

Given that,

Wavelength = λ

For D to be small,

We need to calculate the minimum width

Using formula of minimum width

$D\sin\theta=n\lambda$

$D=\dfrac{n\lambda}{\sin\theta}$

Where, D = width of slit

$\lambda$ = wavelength

Put the value into the formula

$D=\dfrac{n\lambda}{\sin\theta}$

Here, $\sin\theta$ should be maximum.

So. maximum value of $\sin\theta$ is 1

Put the value into the formula

$D=\dfrac{1\times\lambda}{1}$

$D=\lambda$

(b). If the minimum number is 50

Then, the width is

$D=\dfrac{50\times\lambda}{1}$

$D=50\lambda$

(c). If the minimum number is 1000

Then, the width is

$D=\dfrac{1000\times\lambda}{1}$

$D=1000\lambda$

Hence, The minimum value of width for first minima is λ

The minimum value of width for 50 minima is 50λ

The minimum value of width for 1000 minima is 1000λ

4 0

3 years ago

If you lived by the sea, what effect of the moon would you see? Describe the effect.

dolphi86 [110]

Answer:

the changes in waves

Explanation:

the moon has its own gravitational pull thus making waves and the rising tides

8 0

3 years ago

What is the Kinetic Energy of a tennis ball after 40.0cm of freefall?

OlgaM077 [116]

The kinetic energy is the same as the potential energy of raising it 40cm (0.4m). That's mgh where m is mass of ball. Its then 3.924*m, whatever m is equal to in kg.

3 0

3 years ago