Given data
*The given initial velocity of the football is v = 20.2 m/s
*The angle above the horizontal is
*The value of the acceleration due to gravity is a = -9.8 m/s^2
The vertical component of the velocity is calculated as
The formula for the time required by the ball to reach the maximum height is given by the equation of motion as
*Here v_f = 0 m/s is the final velocity of the football at maximum height
Substitute the known values in the above expression as
The total time is taken by the football before it hits the ground is calculated as
Answer:
Velocity = 0.309 m/s
Along negative x axis
Explanation:
A pulse moving to the right along the x axis is represented by the wave function
y(x,t) = 2/ (x - 3t)² + 1
At t =0
y(x,0) = 2/ ((x - 3(0))² + 1)
=2 / (x² + 1)
At t = 1
y(x,t) = 2/ ((x - 3(1))² + 1)
= 2 /(( x - 3)² + 1)
At t = 2
y(x,t) = 2/ ((x - 3(2))² + 1)
= 2 /(( x - 6)² + 1)
For the pulse with expression y(x,t) = 4.5²
The Velocity is
V = 2.7 / 8.73
= 0.309 m/s