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rewona [7]
3 years ago
9

Upon reaching a velocity of 100fps, the pilot of the airplane decides to abort the take off and applies brakes and stops the air

plane in 1000ft. What is the airplane’s deceleration? in absolute value
Physics
1 answer:
maw [93]3 years ago
5 0

Answer:

5ft/s^2

Explanation:

We will use the formula for accelerated motion v_f^2=v_i^2+2ad, which for acceleration it means:

a=\frac{v_f^2-v_i^2}{2d}

<em>In our case</em> our initial velocity is v_i=100ft/s and our final velocity is v_f=0ft/s since it comes to rest, this process while traveling a distance d=1000ft, so we have:

a=\frac{v_f^2-v_i^2}{2d}=\frac{(0m/s)^2-(100ft/s)^2}{2(1000ft)}=-5ft/s^2

Which in absolute value means a deceleration of 5ft/s^2

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3 0
3 years ago
The larger the push, the larger the change in velocity. This is an example of Newton's Second Law of Motion which states that th
Mars2501 [29]

Answer:

According to Newton's 2nd law

The force acting on a body produces acceleration in its direction which is directly propotional to the force but inversly propotinal to the mass of tbe body.

Explanation:

a = F/m

F = ma

Where( F) is force (m) is mass and (a) is acceleration.

6 0
3 years ago
Suppose that in a lightning flash the potential difference between a cloud and the ground is 1.0*109 V and the quantity of charg
nata0808 [166]

Answer:

a) U_{e} = 3 \times 10^{10}\,J, b) v \approx 7745.967\,\frac{m}{s}

Explanation:

a) The potential energy is:

U_{e} = Q \cdot \Delta V

U_{e} = (30\,C)\cdot (1.0\times 10^{9}\,V)

U_{e} = 3 \times 10^{10}\,J

b) Maximum final speed:

U_{e} = \frac{1}{2}\cdot m \cdot v^{2}\\v = \sqrt{\frac{2\cdot U_{e}}{m} }

The final speed is:

v=\sqrt{\frac{2\cdot (3 \times 10^{10}\,J)}{1000\,kg} }

v \approx 7745.967\,\frac{m}{s}

3 0
3 years ago
Need help! What is true about the relationship among wavelength, frequency, and energy in electromagnetic radiation?
lesantik [10]
I believe the answer is D

7 0
3 years ago
Read 2 more answers
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raketka [301]

Answer:

iv) It is 9x bigger than before

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The intensity of the wave, assuming it propagates evenly in all directions, is constant at a given distance from the source, and can be expressed as follows:

I = P/A

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For a sinusoidal wave, the power is proportional to the square of the amplitude, so the intensity is proportional to the square of the amplitude also.

If the amplitude changes increasing three times, the change in intensity will be proportional to the square of the change in amplitude, i.e., it will be 9 times bigger.

So, the statement iv) is the right one.

7 0
3 years ago
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