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3 years ago

An atom of arsenic has how many electron-containing orbitals

Physics

1 answer:

irina [24]3 years ago

8 0

Answer:

The Arsenic has three electron-containing orbitals. The orbitals s, p and d.

Explanation:

Arsenic is an element with an atomic number equal of 33, it means that it has 33 electrons in its orbitals in the following way:

$1s^{2}$

$2s^{2}$

$2p^{6}$

$3s^{2}$

$3p^{6}$

$3d^{10}$

$4s^{2}$

$4p^{3}$

Therefore, the Arsenic has three electron-containing orbitals (s, p d).

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A kayaker paddles at 4.0 m/s in a direction 30° south of west. He then turns and paddles at 3.7 m/s in a direction 20° west of s

vichka [17]

Answer:

Magnitude of resultant velocity of kayaker to the nearest tenth = 10 m/s

Direction of resultant velocity of kayaker = 49.32⁰ South of west.

Explanation:

Let east represents positive x- axis and north represent positive y - axis. Horizontal component is i and vertical component is j.

First kayaker paddles at 4.0 m/s in a direction 30° south of west, kayaker paddles at 4.0 m/s in a direction 210° anticlockwise from positive horizontal axis.

So velocity of kayaker = 4 cos 210 i + 4 sin 210 j = -3.46 i - 2 j

He then turns and paddles at 3.7 m/s in a direction 20° west of south, kayaker paddles at 3.7 m/s in a direction 250° anticlockwise from positive horizontal axis.

So that velocity = -1.27 i - 3.48 j

So resultant velocity of kayaker = -3.46 i - 2 j +(-1.27 i - 3.48 j) = -4.71 i - 5.48 j

Magnitude of resultant velocity of kayaker = $\sqrt{(-4.71)^2+(-5.48)^2} = 7.23 m/s$

Magnitude of resultant velocity of kayaker to the nearest tenth = 10 m/s

Direction of resultant positive horizontal axis, θ = tan⁻¹(-5.48/-4.71) = 229.32⁰ = 49.32⁰ South of west.

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3 years ago

Read 2 more answers

One of the problems with nuclear energy is the potential harm caused by nuclear radiation emitted by the materials used to gener

Serhud [2]

Answer:

.....

why no one is answering??

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3 years ago

What represents the impulse of the force in a graph of force versus time?

vovikov84 [41]

In the graph of the force vs the time:
Force is the gradient of the momentum versus the time.

If we get the area under the curve in this graph:
it will be calculated as : force * time
which gives the change in momentum or the impulse.

Therefore, the area under the curve represents the impulse of the force in a graph of force versus time

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4 years ago

A ball is thrown vertically down from the edge of a cliff with a speed of 4 m/s, how high is the cliff, if it took 12 s for the

Vesna [10]

Answer:

The height of the cliff from which the ball was dropped from is 224.4m.

\overline{v}={\frac{\Delta x}{\Delta t}}

Given the data in the question;

Initial velocity of the ball;

Time taken by the ball to reach the ground;

Distance or Height of the cliff from which the ball was thrown from;

To get the height of the Cliff, we use the Second Equation of Motion:

Where s is the distance or height, is the initial velocity, t is the time and a is the acceleration. Since the ball was thrown down from a certain height (cliff), its is now under the influence of gravity. acceleration due to gravity;

Hence, the equation becomes

We substitute the given values into the equation

Therefore, the height of the cliff from which the ball was dropped from is 224.4m

Explanation:

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3 years ago

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A 26.0-kg crate, starting from rest, is pulled across a floor with a constant horizontal force of 225 N. For the first 11.0 m th

frozen [14]

Answer:

18 m/s

Explanation:

Force is given by mass × acceleration

F = ma

a = F/m

For the first 11.0 m, there is no friction. Hence, the constant force is applied fully on the crate. The acceleration is

a = 225/26.0 m/s²

By the equation of motion, v² = u² + 2as

where v is the final velocity, u is the initial velocity, a is the acceleration and s is the distance travelled.

Using the values for the first part of the motion,

v² = 0² + 2 × 8.65 × 11.0

v = 13.8 m/s

This is the initial velocity for the second part of the motion. This part has friction of coefficient 0.20.

The frictional force = 0.20 × weight = 0.20 × 26.0 × 9.8 = 50.96 N

The effective force moving the crate in the second motion = 225 - 50.96 N = 174.04 N

This gives an acceleration of 174.04/26.0 = 6.69 m/s².

Using parameters for the equation of motion, v² = u² + 2as

v² = 13.8² + 2 × 6.69 × 10 = 324.24

v = 18 m/s

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4 years ago