The stereo uses an energy of
in a time
, therefore the power of the stereo is given by
We also know that the power of an electrical device is related to its voltage, V, and its resistance, R, by the following equation
therefore, we can rearrange the equation to calculate the resistance of the stereo:
Answer:
24,000 m
Explanation:
First find the rocket's final position and velocity during the first phase in the y direction.
Given:
v₀ = 75 sin 53° m/s
t = 25 s
a = 25 sin 53° m/s²
Find: Δy and v
Δy = v₀ t + ½ at²
Δy = (75 sin 53° m/s) (25 s) + ½ (25 sin 53° m/s²) (25 s)²
Δy = 7736.8 m
v = at + v₀
v = (25 sin 53° m/s²) (25 s) + (75 sin 53° m/s)
v = 559.0 m/s
Next, find the final position of the rocket during the second phase (as a projectile).
Given:
v₀ = 559.0 m/s
v = 0 m/s
a = -9.8 m/s²
Find: Δy
v² = v₀² + 2aΔy
(0 m/s)² = (559.0 m/s)² + 2 (-9.8 m/s²) Δy
Δy = 15945.5 m
The total displacement is:
7736.8 m + 15945.5 m
23682.2 m
Rounded to two significant figures, the maximum altitude reached is 24,000 m.
The magnitude of the average force exerted on the ball by the wall is calculated below.
The average force exerted by the ball on the wall is 3 N
Explanation:
Given:
mass of the ball (m)=0.10 kg
speed (v) =3.0 m/s
time taken(t) =0.01 seconds
To calculate:
Average force(F) exerted by ball on the wall
We know;
F=(m×v)÷t
F=(0.10×3.0)÷0.01
<u><em>F=3 N</em></u>
Therefore the average force exerted by the ball on the wall is 3 N
Answer:
74 N
Explanation:
T = Tension in the string = 74 N
= Density of the steel = 7800 kg/m³
A = Area = 
r = Radius = 
Linear density is given by
The linear density is 0.0177 kg/m
Velocity is given by
The velocity of the wave on the guitar string is 64.65903 m/s
Answer:
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Explanation:
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