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Shtirlitz [24]
3 years ago
8

Which behavior describes two sides of a wave moving at different speeds upon entering a medium at an angle? diffraction reflecti

on interference refraction
Physics
2 answers:
s344n2d4d5 [400]3 years ago
8 0

Answer:

refraction

Explanation:

I did Grad Point

alekssr [168]3 years ago
7 0

The answer is refraction. When a wave from one medium enters another medium, its direction changes due to the change of speed (phase velocity changes but frequency remains the same). The wave slows down when it enters a denser medium from the one it came from hence its path seems to bend.

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The greater the amplitude of a wave a. The quieter the sound b. The higher the frequency of the sound c. The dimmer the light in
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Answer:

The greater the amplitude the greater the energy.

(Think of a water wave - which carries greater energy a 1 ft wave or

a 10 ft wave)

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3 years ago
Which equation describes the cosines function for right triangle?
Bogdan [553]

Answer:a

Explanation:

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3 years ago
Describe how newtons third law is related to fluid pressure.
Hatshy [7]
Fish swimming forward in the water, the water gets pushed backward because the fish moving forward is forcing the water to move backward, the motion forward and backward are the same, they are opposite and equal.
3 0
3 years ago
A spherical drop of water carrying a charge of 42 pC has a potential of 620 V at its surface (with V = 0 at infinity). (a) What
iren [92.7K]

Answer:

0.0006091222 m

Explanation:

q = Charge = 42 pC

V = Voltage = 620 V

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

Electric potential is given by (at r = R)

V=\dfrac{q}{4\pi\epsilon R}\\\Rightarrow R=\dfrac{q}{4\pi\epsilon V}\\\Rightarrow R=\dfrac{42\times 10^{-12}}{4\pi\times 8.85\times 10^{-12}\times 620}\\\Rightarrow R=0.0006091222\ m

The radius of the drop is 0.0006091222 m

3 0
3 years ago
A 10.00-kilogram block slides along a horizontal, frictionless surface at 12.0 meters per second for 6.00 seconds. The magnitude
earnstyle [38]

Answer:

120 kg m/s

Explanation:

The magnitude of the momentum of an object is given by

p=mv

where

m is the mass of the object

v is its speed

For the block in this problem,

m = 10.0 kg (mass of the block)

v = 12.0 m/s (speed of the block)

Therefore the magnitude of the block's momentum is

p=(10.0 kg)(12.0 m/s)=120 kg m/s

4 0
3 years ago
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