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Nataly [62]
3 years ago
11

Help me please would be happy if you did

Chemistry
1 answer:
Natasha_Volkova [10]3 years ago
8 0
You have to read the passage and compare and contrast the story
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1)How can scientists use a seismograph to determine the density and depth of Earth's layers?
Masteriza [31]
Hello Olivia!!! 

<span>Q.) Describe at least two geological events that can occur at a divergent boundary.
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A.)Most active divergent plate boundaries occur between oceanic plates and exist as mid-oceanic ridges. Divergent boundaries also form volcanic islands which occur when the plates move apart to produce gaps which molten lava rises to fill.

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3 0
3 years ago
An ionic compound contains an unknown ion X and has the formula X3N2. Ion X contains 10 electrons. Write down the chemical symbo
Delvig [45]

Answer:

Mg3N2

Explanation:

it would be magnesium as it would loss to electron so it would have 10 electron. you can see in the picture above .

hope this helps :)

8 0
3 years ago
What is one of the names for a column in the periodic table?
zheka24 [161]

Answer:

row, period, group

Explanation:

8 0
3 years ago
Read 2 more answers
A chemist designs a galvanic cell that uses these two half-reactions: half-reaction standard reduction potential (s)(aq)(aq)(l)
miv72 [106K]

Answer:

Reduction (cathode): Cu²⁺(⁺aq) + 2 e⁻ → Cu(s)  

Oxidation (anode): Zn(s) → Zn²⁺(⁺aq) + 2 e⁻        

Cu²⁺(⁺aq) + Zn(s) → Cu(s) + Zn²⁺(⁺aq)

E°cell = 1.10 V

Explanation:

<em>The half-reactions are missing, but I will propose some to show you the general procedure and then you can apply it to your equations.</em>

<em>Suppose we have the following half-reactions.</em>

<em>Cu²⁺(⁺aq) + 2 e⁻ → Cu(s)   E°red = 0.34 V</em>

<em>Zn²⁺(⁺aq) + 2 e⁻ → Zn(s)    E°red = -0.76 V</em>

<em />

To identify how to make a spontaneous cell, we need to consider the standard reduction potentials (E°red). The half-reaction with the higher E°red will occur as a reduction (in the cathode), whereas the one with the lower E°red will occur as an oxidation (in the anode).

Reduction (cathode): Cu²⁺(⁺aq) + 2 e⁻ → Cu(s)   E°red = 0.34 V

Oxidation (anode): Zn(s) → Zn²⁺(⁺aq) + 2 e⁻        E°red = -0.76 V

To get the overall equation we add both half-reactions.

Cu²⁺(⁺aq) + Zn(s) → Cu(s) + Zn²⁺(⁺aq)

The standard cell potential (E°cell) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E°cell = E°red, cat - E°red, an

E°cell = 0.34 V - (-0.76 V) = 1.10 V

Since E°cell > 0, the reaction is spontaneous.

5 0
3 years ago
The chemical formula for sulfuric acid is H2SO4. In one molecule of sulfuric acid, there are _____.
erma4kov [3.2K]

Answer:

four atoms of oxygen

Explanation:

two atoms of hydrogen

one sulphur atom

5 0
3 years ago
Read 2 more answers
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