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Oksi-84 [34.3K]
3 years ago
6

A GAS SAMPLE HAS A TEMPERATURE OF 18 CELSIUS WITH AN UNKNOWN VOLUME. THE SAME GAS HAS A VOLUME OF 436 ML WHEN THE TEMPERATURE IS

91 CELSIUS WITH NO CHANGE IN THE PRESSURE AND AMOUNT OF GAS
Chemistry
1 answer:
Alex787 [66]3 years ago
5 0

Answer : The unknown volume will be, 348.6 mL

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles of gas.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=?\\T_1=18^oC=(18+273)K=291K\\V_2=436mL\\T_2=91^oC=(91+273)K=364K

Now put all the given values in above equation, we get:

\frac{V_1}{291K}=\frac{436mL}{364K}\\\\V_1=348.6mL

Therefore, the unknown volume will be, 348.6 mL

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