Answer:
D. protons that is the answer
Answer:
0.940mol &
0.000301mol respectively.
Explanation:
number of moles = given mass / molar mass
given mass of Nacl = 55g Molar mass = 23 + 35.5
n=m/M = 55g/58.5g/mol = 0.940mol
note- (add the atomic weights of sodium and chlorine to get the molar mass of Nacl.) = 58.5g/mol
similarly, NaCO3 = 23 + 12 + 16*3 = 83g/mol
n=m/M = 0.025g/83g/mol = 3.01 * 10^-4 = 0.000301mol
extra: If you ever get asked to put it in number of particles just use the relation of 1mole = 6.02 * 10^23 particles.
Answer:
the rust formed because of the water sitting in sied a metal bowl for long time but they can fix this if they get filters
Explanation:
Answer:
Search Results
Empirical formula of carbon hydrogen and nitrogen
Nitrogen usually forms three bonds one to Carbon and 2 to Hydrogen atoms. Carbon usually forms four bonds one to Nitrogen and 3 to Hydrogen atoms. The empirical formula is CH5N .
Explanation:
Answer:

Explanation:
Given that:-
Moles of K = 1.10 moles
Moles of Te = 0.55 moles
Moles of O = 1.65 moles
Taking the simplest ratio of the moles of the elements as:-
K : Te : O
1.10 : 0.55 : 1.65
2 : 1 : 3
Empirical formulas is the simplest or reduced ratio of the elements in the compound. So, the empirical formula is:- 