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4 years ago

The Si unit of potential difference is a) volt b) JA⁻¹s⁻¹ c)JC⁻¹ d) All the above

Physics

2 answers:

vlabodo [156]4 years ago

7 0

Answer:

a) Volt

Explanation:

The standard metric unit on electric potential difference is the volt.

Gnoma [55]4 years ago

5 0

answer

all of the above

explanation

as we know that the si unit of potential difference is volt

which is equal to j/c and j/c is equal to j/a.s so the correct answer is all of the above

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A mother pats a child every time he throws a chocolate wrapper in the dustbin. This is an example of (A) Observational Learning

TEA [102]

D. I think, not sure

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4 years ago

Monochromatic light is incident on a grating that is 75 mm wide and ruled with 50,000 lines. the second-order maximum is seen at

DIA [1.3K]

Answer:

The wavelength of the incident light is $\lambda =$ 400 nm

Explanation:

Given data

Distance between the sits

$d = \frac{0.075}{50000}$

d = 1.5 × $10^{-6}$ m

$\theta = 32.5$ °

m = 2

We know that the wavelength of the incident light is given by

$\lambda = \frac{d\sin \theta}{m}$

Put all the value in above formula we get

$\lambda = \frac{1.5 (\sin 32.5)}{2}$ × $10^{-6}$

$\lambda =$ 4 × $10^{-7}$ m

$\lambda =$ 400 nm

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4 0

4 years ago

A particle confined to a motion along the x axis moves with a constant acceleration of 2.5m/s2. Its velocity at t=0s is 6m/s. Fi

morpeh [17]

Answer:

v = 16 m/s

Explanation:

It is given that,

Acceleration of a particle along x -axis is $2.5\ m/s^2$

At t = 0s, its velocity is 6 m/s

We need to find the velocity at t = 4 s

It means that the initial velocity of the particle is 6 m/s

Let v is the velocity at t = 4 s

So,

v = u + at

$v=6+2.5\times 4\\\\v=16\ m/s$

So, the velocity at t = 4 s is 16 m/s.

6 0

3 years ago

6. Decelerating a plane at a uniform rate of -8 m/s2, a pilot stops the plane in 484 m. How

uysha [10]

Answer: 88 m/s

Explanation:

If we are talking about an acceleration at a uniform rate, we are dealing with constant acceleration, hence we can use the following equation:

${V_{f}}^{2}={V_{o}}^{2}+2ad$ (1)

Where:

$V_{f}=0$ Is the final velocity of the plane (we know it is zero because we are told the pilot stops the plane at a specific distance)

$V_{o}$ Is the initial velocity of the plane

$a=-8m/s^{2}$ is the constant acceleration of the plane

$d=484m$ is the distance at which the plane stops

Isolating $V_{o}$ from (1):

$V_{o}=\sqrt{-2ad}$ (2)

$V_{o}=\sqrt{-2(-8m/s^{2})(484m)}$ (3)

Finally:

$V_{o}=88m/s$ This is the veocity the plane had before braking began

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3 years ago

Show the relationship between the quantity of matter and the mass of objects

IRISSAK [1]

Answer:

actually quantity of matter present in a body is its mass.

3 0

3 years ago