Answer:
Step-by-step explanation:
The question is not correct (particularly the expression for the area)
A=2lh+2wh
Now we are expected to solve for l, that is we are going to make l subject of the formula, we have
let us take the second term on the RHS to the LHS
we can now divide both sides by 2h we have
hence the expression for the length is
Answer:
(0 , -a²)
Step-by-step explanation:
tangent at x = a and x = -a
y = x² (a , a²) and (-a , a²) must be on the curve and tangent to curve
gradient dy/dx = 2x
slope (m) at x = a is <u>2a</u> and slope (m') at x=-a is<u> -2a</u>
line1: (y - a²) / (x - a) = 2a
y - a² = 2a (x - a) y = 2ax - a² ... (1)
line2: (y - a²) / (x + a) = - 2a y = -2ax- a² ... (2)
(1) - (2): 4ax = 0 a≠0 x = 0
y = - a²
I wish I did it right, or ....
Answer:
y = x + 3
Step-by-step explanation:
Given: (6,9) (14, 17)
slope, m = 1
Equation of line ⇒ y=mx+b
y = 9 , x = 6 , m = 1, b = ?
9 = 1*6 + b
9 = 6 + b
b = 9 - 6 = 3
Therefore, the equation of line will be:
y = 1x + 3
y = x + 3