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Answer: Last option.
Step-by-step explanation:
The equation of the line in Slope-Intercept form is:
Where "m" is the slope of the line and "b" is the y-intercept.
The slope of a line can be found with this formula:
In this case, knowing that this line goes through the points (0,3) and (2,-1), you get that its slope is:
By definition, a line intersects the y-axis when 
.
Since the line goes through the point (0,3), you can identify that:
Then, the equation of this line in Slope-Intercept form, is:
You know that everything to the left of the dashed line is shaded, then the symbol of the inequality is 
.
Therefore, the linear inequality that is represented by the graph is:
2. Create frequency tables to represent the morning and afternoon dogs as two sets of data. Group the weights into classes that range 10 pounds. (4 points: 2 points for appropriate intervals, 2 points for correctly portraying data)
Morning
Range
Dogs
10 to 19
3
20 to 29
4
30 to 39
3
Afternoon
Range
Dogs
0 to 9
2
10 to 19
3
20 to 29
1
30 to 39
2
40 to 49
1
50 to 59
1
3. What is the median of the morning (AM) group? What is the median of the afternoon (PM) group? (2 points: 1 point for each answer)
Morning (AM): 25.5
Afternoon (PM): 19
4. What is the first quartile (Q1) of the morning (AM) group? What is the first quartile (Q1) of the afternoon (PM) group? (2 points: 1 point for each answer)
Morning (AM): 10
Afternoon (PM): 0
5. What is the third quartile (Q3) of the morning (AM) group? What is the third quartile (Q3) of the afternoon (PM) group? (2 points: 1 point for each answer)
Morning (AM): 20
Afternoon (PM): 10
6. What is the interquartile range (IQR) of the morning (AM) group? What is the interquartile range (IQR) of the afternoon (PM) group? (2 points: 1 point for each answer)
Morning (AM): 39
Afternoon (PM): 29
7. The average weights of the dogs are the same for the morning and afternoon groups. But based on your comparative box plot and the IQRs of the two groups, which group of dogs does you think would be easier to walk as one group? Why? (2 points: 1 point for the answer, 1 point for justification)
The morning dogs, there are fewer dogs and they seem to weigh less.
All of the answers I have here!
Answer:
f(g(x)) = 3(2x^3 -2)^2 - 4x + 2, and f(g(3)) = 3[2(3)^3 -2]^2 -4*3 -2 = 8102
Step-by-step explanation:
because for f(g(x)), the g(x) is the input of f(x), so put 2x^3 -2 into 3x^2 -4x +2, and you will get f(g(x)). because g(3) is the input of f(x), so find g(3) first, the answer is 52, and then put it back into f(x) which will be f(52) =[3(52)^2 - 4(3) +2], then the answer should be 8102.
