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3 years ago

State a hypothesis about your estimated daily water use.

Physics

2 answers:

Kryger [21]3 years ago

6 0

Answer

Estimates vary, but, on average, each person uses about 80-100 gallons of water per day, for indoor home uses.

Explanation:

satela [25.4K]3 years ago

4 0

Answer:

rdyrd

Explanation:

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What do we call patterns in the sky

Studentka2010 [4]

I think it would be constellations

7 0

4 years ago

Distance in scientific notation

n200080 [17]

Answer:

(See explanation for further information)

Explanation:

a) The distances of each planet with respect to the Sun is:

Mercury - $57.909 \times 10^{6}\,mi$

Venus - $67.240\times 10^{6}\,mi$

Earth - $92.960\times 10^{6}\,mi$

Mars - $141.600\times 10^{6}\,mi$

Jupiter - $483.800\times 10^{6}\,mi$

Saturn - $888.200\times 10^{6}\,mi$

Uranus - $1,787\times 10^{6}\,mi$

Neptune - $2,795\times 10^{6}\,mi$

b) The solutions are presented below:

A. The distance between Venus and Jupiter is:

$\Delta s = 483.800\times 10^{6}\,mi-67.240\times 10^{6}\,mi$

$\Delta s = 416.560\times 10^{6}\,mi$

B. The combined distance from the Sun is:

$\Delta s = 57.909\times 10^{6}\,mi + 67.240\times 10^{6}\,mi +92.960\times 10^{6}\,mi$

$\Delta s = 218.109\times 10^{6}\,mi$

Which is less than the distance from the Sun to Neptune ( $2,795\times 10^{6}\,mi$ ).

C. The new distance of Earth is $929.60 \times 10^{6}\,mi$ ( $929,600,000\,mi$ ). Saturn would be the closest planet to Earth, whose distance:

Scientific notation:

$\Delta s = 929.600\times 10^{6}\,mi-888.200\,\times 10^{6}\,mi$

$\Delta s = 41.4\times 10^{6}\,mi$

Standard notation:

$\Delta s = 929,600,000\,mi - 888,200,000\,mi$

$\Delta s = 41,400.000\,mi$

3 0

4 years ago

a mountain biker cycling a trail traveling at 5.4 m/s begins to slow down when she notice a wooden bridge ahead has flooded. if

andrew-mc [135]

Answer:

t = 5.56 s

Explanation:

In order to calculate the time interval taken by the mountain biker to come to a stop, we will use third equation of motion and first find the deceleration:

2as = Vf² - Vi²

where,

a = deceleration = ?

s = distance = 15 m

Vf = Final Velocity = 0 m/s

Vi = Initial Velocity = 5.4 m/s

Therefore,

2a(15 m) = (0 m/s²) - (5.4 m/s)²

a = - 0.972 m/s²

Now, we use 1st equation of motion:

Vf = Vi + at

therefore,

0 m/s = 5.4 m/s + (-0.972 m/s²)(t)

t = (5.4 m/s)/(0.972 m/s²)

5 0

3 years ago

The equation of a progressive

Juliette [100K]

Answer:

Amplitude = 0.02m

Frequency = 640 Hz

Wavelength, λ = 0.5m

v = 320 m/s

Explanation:

Given the wave equation :

y=0.02 sin2π/0.5 (320t - x) where x and y are in

meters and t is in second

Comparing the above relation with the general wave equation :

y(x, t) = Asin2π/λ(wt - kx)

The amplitude, A = 0.02

From the equation :

2π/0.5 = 2π/λ

λ = 0.5 m

320t = vt

Hence, v = 320 m/s

Recall :

v = fλ

320 = f * 0.5

f = 320 / 0.5

f = 640 Hz

6 0

3 years ago

Two musicians are comparing their trombones. The first produces a tone that is known to be 438 Hz. When the two trombones play t

galben [10]

Answer:

It is producing either a 435-Hz sound or a 441-Hz sound.

Explanation:

When two sound of slightly different frequencies interfere constructively with each other, the resultant wave has a frequency (called beat frequency) which is equal to the absolute value of the difference between the individual frequencies:

$f_B = |f_1 -f_2|$ (1)

In this problem, we know that:

- The frequency of the first trombone is $f_1 = 438 Hz$

- 6 beats are heard every 2 seconds, so the beat frequency is

$f_B=\frac{6}{2 s}=3 Hz$

If we insert this data into eq.(1), we have two possible solutions for the frequency of the second trombone:

$f_2 = f_1 - f_B = 438 Hz - 3 Hz = 435 Hz\\f_2 = f_1+f_B = 438 Hz+3 Hz=441 Hz$

7 0

3 years ago