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castortr0y [4]
4 years ago
11

IF YOU ANSWER ALL I WILL GIVE A BRAINLIEST... ONLY 3 QUESTIONS!

Physics
1 answer:
Law Incorporation [45]4 years ago
6 0

Answer: a) electromagnetic waves

Explanation:

An electromagnetic wave begins when an electrically charged particle vibrates. This causes a vibrating electric field, which in turn creates a vibrating magnetic field. The two vibrating fields together form an electromagnetic wave.

Hope this helps:)

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an athlete sprints from 150 m south of the finish line to 65 m south of the finish line in 5.0s what is his average velocity
MatroZZZ [7]
  • Total displacement=150-65m=85m
  • Time=5s

\\ \rm\longrightarrow Avg\:Velocity=\dfrac{Total\:Displacement}{Total\:Time}

\\ \rm\longrightarrow Avg\:Velocity=\dfrac{85}{5}

\\ \rm\longrightarrow Avg\:Velocity= 17m/s

6 0
3 years ago
Read 2 more answers
Which type of radioactive decay results in no change in mass number and atomic number for the starting nucleus?
Volgvan

Answer:

Gamma Rays

Explanation:

For the starting nucleus, the gamma rays is the type of radioactive decay results in no change in mass number and atomic number. This is only due to the fact that gamma rays don't have any mass and also don't have any kind of electric charge. So after decaying it shows no sign of change in atomic number because neither the mass has changed nor the charge.

7 0
3 years ago
The electric field everywhere on the surface of a thin, spherical shell of radius 0.750 m is of magnitude 890 N/C and points rad
andrezito [222]

Answer:

55.6 nC

Explanation:

The electric field at the surface of a charged sphere has the same expression of the electric field produced by a single point charge located at the centre of the sphere and having the same charge of the sphere, so it is given by

E=k\frac{Q}{r^2}

where

k=9\cdot 10^9 N m^2 C^{-2} is the Coulomb's constant

Q is the charge on the sphere

r is the radius of the sphere

In this problem we know

E = 890 N/C is the magnitude of the electric field on the sphere

r = 0.750 m is the radius of the sphere

So by re-arranging the equation we can find the net charge on the sphere:

Q=\frac{Er^2}{k}=\frac{(890)(0.750)^2}{9\cdot 10^9}=5.56\cdot 10^{-8} C=55.6 nC

5 0
4 years ago
When hoisting a personnel platform which of the following need not be engaged when they occupied platform is in a stationary pos
aivan3 [116]
The answer is <span>Guardrails and protective equipment.   </span><span>When hoisting a personnel platform, guardrails and protective equipment need not be engaged when they occupied platform is in a stationary position.  </span>
3 0
4 years ago
Calculating If the average or normal temperature decrease with altitude in the troposphere is 6.5°C/km, calculate the approximat
grigory [225]

Answer:

- The temperature of 10°C will be experienced at an altitude of 2.52 km

- The temperature of 0°C will be experienced at an altitude of 4.15 km

Explanation:

Lapse Rate = -6.5°C/km of ascent.

Lapse Rate = Temperature difference/altitude difference

For the 10°C,

Temperature difference = 10 - 27 = -17°C

-6.5 = -17/(difference in altitude between the two points)

Difference in altitude = 17/6.5 = 2.52 km

For 0°C,

Temperature difference = 0 - 27 = - 27°C

-6.5 = -27/(difference in altitude between the two points)

Altitude difference = 27/6.5 = 4.15 km

5 0
3 years ago
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