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Triss [41]
3 years ago
12

A student has a balloon that looks shiny like a metal and wants to perform an experiment to determine if it contains any metal.

Which of the following procedures could possibly determine if the balloon contains metal? Charge the balloon, hold it near an electroscope, and determine if the electroscope leaves move. Charge the balloon, hold it near an electroscope, and determine if the electroscope leaves move.
A. Charge the balloon, hold it near small pieces of paper, and see if it picks up any of the paper. Charge the balloon, hold it near small pieces of paper, and see if it picks up any of the paper.
B. Hold a positively charged rod near the uncharged balloon, then hold a negatively charged rod near the uncharged balloon, and observe whether the balloon acquires a net charge. Hold a positively charged rod near the uncharged balloon, then hold a negatively charged rod near the uncharged balloon, and observe whether the balloon acquires a net charge.
C. Hold a positively charged rod near the uncharged balloon, then hold a negatively charged rod near the uncharged balloon, and observe whether the balloon is attracted or repelled by the rods.
Chemistry
1 answer:
zheka24 [161]3 years ago
3 0

Answer:

Charge the balloon, hold it near an electroscope, and determine if the electroscope leaves move.

Explanation:

The gold leaf electroscope is an instrument used to detect if a body is charged. It has two gold leafs suspended from a brass stem in a vacuumed glass jar and connected to a metal cap(Toppr).

When the test body is allowed to touch the metal cap, a change in the size of the leaves shows whether the body is charged or not.

Since we are suspecting the balloon to be made up of a metal; metals can be charged. We can test if there is really a charge on the balloon by bringing it near an electroscope to see if the electroscope moves.

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How many moles of co2 can be produced by the complete reaction of 1.53 g of lithium carbonatewith excess hydrochloric acid (bala
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Determine the mass (in grams) of 8.02 x 1024 atoms of mercury (Hg).
Virty [35]
<h3>Answer:</h3>

2670 g Hg

<h3>General Formulas and Concepts: </h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation: </h3>

<u>Step 1: Define</u>

8.02 × 10²⁴ atoms Hg

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Hg - 200.59 g/mol

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 8.02 \cdot 10^{24} \ atoms \ Hg(\frac{1 \ mol \ Hg}{6.022 \cdot 10^{23} \ atoms \ Hg})(\frac{200.59 \ g \ Hg}{1 \ mol \ Hg})
  2. Divide/Multiply:                                                                                               \displaystyle 2671.42 \ g \ Hg

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

2671.42 g Hg ≈ 2670 g Hg

3 0
3 years ago
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