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dedylja [7]
3 years ago
11

How does light travel from our light source? What kind of light is it and what is it made of?

Physics
2 answers:
suter [353]3 years ago
4 0

Answer:

light is a form of energy produced by a light source. Light is made of photons that travel very fast. Photons of light behave like both waves and particles

Explanation:

lisabon 2012 [21]3 years ago
4 0

Answer:

it travels through a beam

it's is artificial light ...................

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a police car drives with a constant speed of 24 miles per hour .how long will it take to travela distance of 72 miles​
leonid [27]

This problem is an exact copy of the other one that I just answered for you, about Grace driving 224 miles.  

Only the numbers are different, but the way to solve it is exactly the same.

6 0
3 years ago
At an amusement park, a swimmer uses a water slide to enter the main pool. a. If the swimmer starts at rest, slides with negligi
adoni [48]

Answer:

a)6.7m/S

b)6.8m/s

Explanation:

Hello ! To solve the point b you must follow the steps below

1.Draw the slide taking into account its length and height and find the angle from which the swimmer is launched (see attached image)

2. Find the horizontal velocity (X) and vertical (Y) components (see attached image)

3) for the third step we must remember that as in the slide there is no horizontal acceleration the speed in X will remain constant at the end of the swimmer's path (Vx = 0.59m / s)

4)

the fourth step is to remember that vertically there is constant acceleration called gravity (g = 9.81m / s ^ 2), so to find the speed at the end of the route we use the following equation

Vfy= \sqrt{Vy^2+2gy}

where    

Vfy= final verticaly speed    

Vy=initial verticaly speed=0.59m/S

g=gravity=9.81m/S^2

y=height of slide=2.31m

solving

Vfy= \sqrt{Vy^2+2gy}\\Vfy= \sqrt{(0.59)^2+2(9.81)(2.31)}=6.77m/s

The last step is to add the velocity components vectorally at the end of the route with the following equation

V=\sqrt{Vfy^2+Vx^2} =\sqrt{6.77^2+0.59^2} =6.8m/s

point A

taking into account the previous steps we can infer that as the swimmer starts from rest, the velocity (Vx=Vy=O) is zero, so we should only use the formula for constant acceleration movement.

Vfy= \sqrt{Vy^2+2gy}

vy=0

Vfy=\sqrt{2gy}

Vfy=\sqrt{2(9.81)(2.31)}=6.7m/s

8 0
3 years ago
Alfredo leaves camp and, using a compass, walks 4 km E, then 6 km S, 3 km E, 5 km N, 10 km W, 8 km N, and, finally, 3 km S. At t
kari74 [83]

Answer: 3km E, 1km N

Explanation:

4E + 6S + 3E + 5N + 10W + 8N + 3S= 3W, 1S

3W, 1S= 3E, 1N

8 0
2 years ago
What is lower body strength
Lerok [7]
Lower body strength is the ability of the body to exert a maximum force against an object external to the body in one maximum effort of the lower body muscles. Gluteals are muscles that make up the buttocks. ... Their roles are to facilitate hip extension and lift the leg to the side.
3 0
3 years ago
Read 2 more answers
A heavy ball with a weight of 100 NN is hung from the ceiling of a lecture hall on a 4.4-mm-long rope. The ball is pulled to one
allochka39001 [22]

Answer:

175.3 N

Explanation:

The motion of the ball is a uniform circular motion, therefore the net force on it must be equal to the centripetal force.

There are two forces acting on the ball at the lowest point of motion:

- The tension in the string, T , upward

- The weight of the ball, mg, downward

The net force (centripetal force) has the same direction as the tension (upward, towards the centre of the circular path), so we can write:

T-mg=m\frac{v^2}{r}

where the term on the right is the expression for the centripetal force, and where:

T is the tension in the string

mg=100 N is the weight of the ball

m=\frac{mg}{g}=\frac{100}{9.8}=10.2 kg is the mass of the ball

v = 5.7 m/s is the speed of the ball at the lowest point

r = 4.4 m is the length of the rope, so the radius of the circle

Solving for T, we find the tension in the string:

T=mg+m\frac{v^2}{r}=(100)+(10.2)\frac{5.7^2}{4.4}=175.3 N

7 0
4 years ago
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