Answer: -
2.5 mL
Explanation: -
Volume of final solution = 10 mL
Strength of final solution = 10 mg / mL
Amount of drug required = Volume of final solution x strength of final solution
= 10 mL x 10 mg/ mL
= 100 mg.
Strength of supplied drug = 40mg/ mL
Volume of supplied drug required = 
= 2.5 mL
Thus to make 10 ml of a 10 mg/ml solution. 2.5 mL will be needed.
Answer:
92.6 g.
Explanation:
- The balanced equation is:
CaC₂ + N₂ → CaCN₂ + C.
- It is clear that 1.0 mole of CaC₂ reacts with 1.0 mole of N₂ to produce 1.0 mole of CaCN₂ and 1.0 mole of C.
- We need to calculate the no. of moles of 265.0 g of CaCN₂ produced using the relation:
n = mass / molar mass = (265.0 g) / (80.102 g/mol) = 3.308 mol.
- We should get the no. of moles of N₂ needed to produce 3.308 mol of CaCN₂.
∵ 1.0 mole of N₂ produces → 1.0 mole of CaCN₂.
<em>∴ 3.308 mole of N₂ produces → 3.308 mole of CaCN₂.</em>
- Now, we can get the grams of N₂ consumed to produce 265.0 g of CaCN₂:
∴ The grams of N₂ = n x molar mass = (3.308 mole)(28.0 g/mol) = 92.63 g = 92.6 g.
Hello,
Here is your answer:
The proper answer to this question is option C "stigma".
Here is how:
The stigma is responsible for producing pollen in a plant.
Your answer is C.
If you need anymore help feel free to ask me!
Hope this helps!
