Answer
given,
height of window = 4 m
time taken to travel = 1 s
acceleration due to gravity = 9.8 m/s²
![s = ut + \dfrac{1}{2}at^2](https://tex.z-dn.net/?f=s%20%3D%20ut%20%2B%20%5Cdfrac%7B1%7D%7B2%7Dat%5E2)
![u = \dfrac{s - \dfrac{1}{2}at^2}{t}](https://tex.z-dn.net/?f=u%20%3D%20%5Cdfrac%7Bs%20-%20%5Cdfrac%7B1%7D%7B2%7Dat%5E2%7D%7Bt%7D)
![u = \dfrac{4 - \dfrac{1}{2}\times 9.8\times 1^2}{1}](https://tex.z-dn.net/?f=u%20%3D%20%5Cdfrac%7B4%20-%20%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%209.8%5Ctimes%201%5E2%7D%7B1%7D)
u = -0.905 m/s
initial velocity of ledge v = 0
now,
v² = u² + 2 a s
(-0.905)² = 0 + 2 × 9.8 ×s
s = 0.042 m
Answer:
0.8
Explanation:
The two spheres have the same potential, V.
Let the radius of the larger sphere be R and the radius of the smaller sphere be r,
=> R = 4r
Let the charge on the smaller sphere be q. Hence, the larger sphere will have charge Q - q.
The potential of the smaller sphere will be:
![V_S = \frac{kq}{r}](https://tex.z-dn.net/?f=V_S%20%3D%20%5Cfrac%7Bkq%7D%7Br%7D)
The potential of the larger sphere will be:
![V_L = \frac{k(Q - q)}{R}](https://tex.z-dn.net/?f=V_L%20%3D%20%5Cfrac%7Bk%28Q%20-%20q%29%7D%7BR%7D)
Inputting R = 4r,
![V_L = \frac{k(Q - q)}{4r}](https://tex.z-dn.net/?f=V_L%20%3D%20%5Cfrac%7Bk%28Q%20-%20q%29%7D%7B4r%7D)
Since
,
![\frac{k(Q - q)}{4r} = \frac{kq}{r}](https://tex.z-dn.net/?f=%5Cfrac%7Bk%28Q%20-%20q%29%7D%7B4r%7D%20%3D%20%5Cfrac%7Bkq%7D%7Br%7D)
=> Q - q = 4q
=> 5q = Q
q = 0.2Q
The fraction of the charge Q that rests on the smaller sphere is 0.2
The charge of the larger sphere is:
Q - q = Q - 0.2Q = 0.8Q
∴ The fraction of the total charge Q that rests on the larger sphere is 0.8
Answer:
No
Explanation:
No because like my other answer if we put to many diesels on it it will crack and little by little it will break eventually everyone will come tumbling into the water making them drown because they can't get the buckles loose or they wanted to save their families lives
Static electricity can be an alternating current.