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Oduvanchick [21]
3 years ago
14

Write a hypothesis about the effect of the magnet polarity on the induced current. Use the "if . . . then . . . because . . ." f

ormat and be sure to answer the lesson question: "How does magnetic polarity affect the current flowing in a loop of wire?"
Physics
2 answers:
klemol [59]3 years ago
7 0

Explanation :

The induced current also depends on the polarity of the magnet. Mathematically, it is given as :

E=-B\dfrac{d\phi}{dt}

E is the induced emf, E = IR

B is the magnetic field

\dfrac{d\phi}{dt} is the rate of change of magnetic flux.

I=-\dfrac{B}{R}\dfrac{d\phi}{dt}

I is the induced current.

The direction of electromagnetic force is determined by polarity of the magnet.

If the polarity of the magnet is reversed then the induced current will also reversed because the direction of electromagnetic force depends on the polarity of the magnet.

Simora [160]3 years ago
3 0
<span>If the polarity of a moving magnet is reversed, then the current induced in a loop of wire will reverse in direction, because magnet polarity determines the direction of the electromagnetic force.</span>
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To reduce inductive reactance, what devices are normally placed on transmission or distribution lines?
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Answer : Capacitors

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2 years ago
In a 350-m race, runner A starts from rest and accelerates at 1.6 m/s^2 for the first 30 m and then runs at constant speed. Runn
kifflom [539]

Answer:

B can take 0.64 sec for the longest nap .

Explanation:

Given that,

Total distance = 350 m

Acceleration of A = 1.6 m/s²

Distance = 30 m

Acceleration of B = 2.0 m/s²

We need to calculate the time for A

Using equation of motion

s=ut+\dfrac{1}{2}at_{A}^2

Put the value in the equation

30=0+\dfrac{1}{2}\times1.6\times t_{A}^2

t_{A}=\sqrt{\dfrac{30\times2}{1.6}}

t_{A}=6.12\ sec

We need to calculate the time for B

Using equation of motion

s=ut+\dfrac{1}{2}at_{B}^2

Put the value in the equation

30=0+\dfrac{1}{2}\times2.0\times t_{B}^2

t_{B}=\sqrt{\dfrac{30\times2}{2.0}}

t_{B}=5.48\ sec

We need to calculate the time for longest nap

Using formula for difference of time

t'=t_{A}-t_{B}

t'=6.12-5.48

t'=0.64\ s

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4 0
3 years ago
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3 years ago
Read 2 more answers
A circular loop with radius r is rotating with constant angular velocity ω in a uniform electric field with magnitude E. The axi
inn [45]

Answer:

\Phi_{E} = E\pi r^2 \omega t

Explanation:

The electric flux is defined as the multiple of electric field and the area that the electric field passes through, such that

\Phi_{E} = \vec{E}\vec{A}

When calculating the electric flux, the angle between the directions of electric field and the area becomes important, especially if the angle is changing with time.

The above formula can be rewritten as follows

\Phi_{E} = EA\cos(\theta)

where θ is the angle between the electric field and the area of the loop. Note that, the direction of the area of the loop is perpendicular to the plane of the loop.

If the loop is rotating with constant angular velocity ω, then the angle can be written as follows

\theta = \omega t

At t = 0, cos(0) = 1 and the electric flux through the loop is at its maximum value.

Therefore the electric flux can be written as a function of time

\Phi_{E} = E\pi r^2 \omega t

3 0
3 years ago
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