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3 years ago

7

A crate slides down a ramp that makes a 20o angle with the ground. To keep the crate moving at a steady speed, Paige pushes back

on it with a 68 N horizontal force. How much work does Paige do on the crate at is slides 3.5 m down the ramp?

1 answer:

cupoosta [38]3 years ago

6 0

Answer:

-223.64684 J

Explanation:

F = Force that is applied to the crate = 68 N

s = Displacement of the crate = 3.5 m

$\theta$ = Angle between the force and displacement vector = (180-20)

Work done is given by

$W=Fscos\theta\\\Rightarrow W=68\times 3.5\times cos(180-20)\\\Rightarrow W=-223.64684\ J$

The work that Paige does on the crate is -223.64684 J

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Explanation:

We are given;. Initial velocity; u = 2 m/s

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2 years ago

The magnetic field at 8 cm distance from a long straight wire, carrying is 0.2x10^-5 T. How much is the electric current in the

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Magnetic Field Calculation

We cleared (I) of the formula (1):

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3 years ago

Will give brainliest to correct answer!

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3 years ago

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Explanation:

Given that,

Capacitor $C=1.66\ \mu F$

Resistor $R=80.0\ \Omega$

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$f_{c}=\dfrac{1}{2\pi R C}$

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Using formula of $V_{R}$

$V_{R}=V_{0}(\dfrac{R}{\sqrt{R^2+(\dfrac{1}{2\pi fC})^2}})$

Put the value into the formula

$V_{R}=5.10\times(\dfrac{80.0}{\sqrt{(80.0)^2+(\dfrac{1}{2\pi\times\dfrac{1}{2}\times1198.45\times1.66\times10^{-6}})^2}})$

$V_{R}=2.280\ Volt$

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Using formula of $V_{R}$

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Using formula of $V_{R}$

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Hence, This is the required solution.

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Answer:

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Therefore, the correct option is:

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2 years ago