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sdas [7]
3 years ago
15

How do you increase capacitance in a capacitor?

Physics
1 answer:
Marizza181 [45]3 years ago
4 0

If you want to increase the Capacitance of Parallele Plate Capacitor then increase the surface area, reduce the separation between the plate and use a dielectric material in between the plate which have higher dielectric breakdown strength.

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Name two types of evidence used to support the theory of evolution. Explain how scientists use each type of evidence to provide
bearhunter [10]
Well, one of the theories was that Charles darwin proved that theory evolution is real so that one theory. 
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3 years ago
1-5 answer please .....
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3 years ago
Solve: A car travels 2 km North , 10 km East, then 3 km West. pythagorean theorem
Evgen [1.6K]

________b_____ 7 km east

|

| 2km north.

|a

|

°

pythagorean theorem : ✓a² + b² = c²

c² = a² + b² = 4 + 49 = 53

c = ✓53 km

displacement = c = ✓53 km

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5 0
3 years ago
A 5.00 g bullet traveling 355 m/s is stopped by lodging in the side of a building. The heat produced is shared between the build
steposvetlana [31]

Answer:

Explanation:

Given

mass of bullet m=5\ gm

speed of bullet v=355\ m/s

bullet is stopped by building and heat produced is shared between building and bullet

Kinetic Energy of bullet is converted into Thermal energy

Kinetic Energy of bullet K=\frac{1}{2}mv^2

K=0.5\times 5\times 10^{-3}\times (355)^2

K=315.06\ J

So 315.06 J of Energy is converted in to thermal energy

7 0
3 years ago
Consider a circuit with a main wire that branches into two other wires. If the current is 10 A in the main wire and 4 A in one o
k0ka [10]

If the primary wire's power is 10 A and one branch's power is 4 A, another branch's power will be 6A.

According to Kirchhoff's current law (KCL), the total current flowing through a parallel route circuit's junction equals the total current flowing away from it.

Provided that one of the two branches through which power exits the intersection has a flow of 4A, and also that the junction's overall flow entering it is 10A, the entire current going the junction should be 10A.

Consequently, the second wire's power may be expressed as;

I = I1+ I2 [ where I= total current (10A);

                I1= current in one branch (4A) &

                I2= current in another branch]

⇒I2 = I - I1

⇒I2 = 10A - 4A

⇒I2 = 6A

Therefore, it can be concluded that when the primary wire bears 10A power having 4A in one of its branches, another branch carries 6A power.

Learn more about Kirchhoff's law here:

brainly.com/question/6417513

#SPJ4

4 0
2 years ago
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