Answer:
answer is
Explanation:
average power each panel produces = 21700/ 5×10^6
4340 ×10^-6
that's mean 4340 micro Watt
Answer:
Explanation:
7a) t = d/v = 100/45cos14.5 = 2.29533...= 2.30 s
7b) h = ½(9.81)(2.29533/2)² = 6.46056... = 6.45 m
or
h = (45sin14.5)² / (2(9.81)) = 6.47 m
which rounds to the same 6.5 m when limiting to the two significant digits of the initial velocity.
Answer:
The moon Phobos orbits Mars
(mass = 6.42 x 1023 kg) at a distance
of 9.38 x 106 m. What is its period of
orbit?
Explanation:
Answer: 27.9816 x 10^3 is the period of orbit
Answer:
![sin\theta - \mu_k cos\theta = \frac{m}{M}](https://tex.z-dn.net/?f=sin%5Ctheta%20-%20%5Cmu_k%20cos%5Ctheta%20%3D%20%5Cfrac%7Bm%7D%7BM%7D)
![sin\theta - \mu_k cos\theta = 1](https://tex.z-dn.net/?f=sin%5Ctheta%20-%20%5Cmu_k%20cos%5Ctheta%20%3D%201)
Explanation:
Force of friction on M mass so that it will move down the inclined plane is given as
![F_f = \mu Mgcos\theta](https://tex.z-dn.net/?f=F_f%20%3D%20%5Cmu%20Mgcos%5Ctheta)
now if it is moving down the inclined plane at constant speed
so we will have
![Mgsin\theta - T - \mu mgcos\theta = 0](https://tex.z-dn.net/?f=Mgsin%5Ctheta%20-%20T%20-%20%5Cmu%20mgcos%5Ctheta%20%3D%200)
on other side the mass "m" will go up at constant speed
so we have
![T - mg = 0](https://tex.z-dn.net/?f=T%20-%20mg%20%3D%200)
so we have
![Mgsin\theta = \mu Mgcos\theta + mg](https://tex.z-dn.net/?f=Mgsin%5Ctheta%20%3D%20%5Cmu%20Mgcos%5Ctheta%20%2B%20mg)
so we have
![sin\theta - \mu_k cos\theta = \frac{m}{M}](https://tex.z-dn.net/?f=sin%5Ctheta%20-%20%5Cmu_k%20cos%5Ctheta%20%3D%20%5Cfrac%7Bm%7D%7BM%7D)
for special case when m = M
then we have
![sin\theta - \mu_k cos\theta = 1](https://tex.z-dn.net/?f=sin%5Ctheta%20-%20%5Cmu_k%20cos%5Ctheta%20%3D%201)
I think the correct answer from the choices listed above is option A. The kinetic energy after the perfectly inelastic collision would be zero Joules. <span>A </span>perfectly inelastic collision<span> occurs when the maximum amount of kinetic energy of a system is lost. Hope this answers the question.</span>