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Mariana [72]
3 years ago
10

1. The resultant force on a ball is not zero. What will happen to the ball? *

Physics
1 answer:
Tju [1.3M]3 years ago
7 0

Answer:

it will more and change direction

Explanation:

because the resultant force (R) is not equal zero so may be there is a force greater than the other one and the ball will more in the direction of greater force.

and it can't be remain stationary because R=! 0 .

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If you are pushing on a box with a force of 20 N and there is a 7 N force on the box due to sliding friction, what is the net fo
vovangra [49]

Answer:

13 N

Explanation:

The Net Force of an object should be the difference between the forces applied to the object if the object is not in equilibrium. This object is not in equilibrium so therefore by finding the difference between the forces, you will find your answer. 20 N - 7 N = 13 N.

6 0
3 years ago
Read 2 more answers
A 0.1 kg toy contains a compressed spring. when the spring is released the toy fly 0.45 m upwards from ground level before falli
trapecia [35]

The speed of the toy when it hits the ground is 2.97 m/s.

The given parameters;

  • mass of the toy, m = 0.1 kg
  • the maximum height reached by the, h = 0.45 m

The speed of the toy before it hits the ground will be maximum. Apply the principle of conservation of mechanical energy to determine the maximum speed of the toy.

P.E = K.E

mgh_{max} = \frac{1}{2} mv_{max}^2\\\\gh_{max} = \frac{1}{2} v_{max}^2\\\\v_{max}^2= 2gh_{max}\\\\v_{max} = \sqrt{2gh_{max}}

Substitute the given values and solve the speed;

v_{max} = \sqrt{2\times 9.8 \times 0.45} \\\\v_{max} = 2.97 \ m/s

Thus, the speed of the toy when it hits the ground is 2.97 m/s.

Learn more here: brainly.com/question/7562874

7 0
2 years ago
A weight lifter applies an upward force of 1100 N while lowering a dumbbell
Paul [167]

Answer:

A

Explanation:

work = force \times distance

work = 1100 \times 0.5

= 550 \: j

hope it helped a lot

pls mark brainliest with due respect .

6 0
3 years ago
A 3.35 kg object initially moving in the positive x direction with a velocity of 4.90 m s collides with and sticks to a 1.88 kg
ahrayia [7]

Answer:

The final components of velocity of the composite object is 3.33 m/s.

Explanation:

Given;

mass of the first object, m₁ = 3.35 kg

initial velocity of the first object, u₁ = 4.90 m/s in positive x-direction

mass of the second object, m₂ = 1.88 kg

initial velocity of the second object, u₂ = 3.12 m/s in negative y-direction

initial momentum of the first object, P₁ = 3.35 x 4.9 = 16.415 kgm/s

initial momentum of the second object, P₂ = 1.88 x 3.12 = 5.8656 kgm/s

The resultant velocity of the two objects is given by;

R² = 16.415² + 5.8656²

R² = 303.858

R = √303.858

R = 17.432 kgm/s

Apply the principle of conservation of linear momentum for inelastic collision;

total initial momentum before = total final momentum after collision

P₁(x) + P₂(y) = Pf

R = Pf

R = v(m₁ + m₂)

17.432 = v(m₁ + m₂)

where;

v is the final components of velocity of the composite object

v = \frac{17.432}{m_1 + m_2} \\\\v = \frac{17.432}{3.35+1.88} \\\\v = 3.33 \ m/s

Therefore, the final components of velocity of the composite object is 3.33 m/s.

8 0
2 years ago
Phosphate never enters the<br> O atmosphere<br> O ground<br> O water<br> O ocean
gizmo_the_mogwai [7]
I think you can google this because I really don’t know the answer I’m so sorry
7 0
3 years ago
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