Answer:
Normal force, N = 154.5 N
Explanation:
Given that,
Total mass of the cart, m = 20.4 kg
Angle of inclination, 
Distance moved, d = 20.1 m
The coefficient of kinetic friction between ground and cart is 0.6
The value of acceleration due to gravity, 
Let N is the normal force exerted on the cart by the floor. It is given by :




T = 103.23 N
So, the normal force is :

N = 154.5 N
So, the normal force exerted on the cart by the floor is 154.5 N. Hence, this is the required solution.
The average speed of the runner is 8.7m/s.
Therefore, Option C) 8.7m/s is the correct answer.
Given the data in the question;
Distance covered; 
Time taken; 
Average speed; 
Speed is the rate at which an object covers a certain distance. It is expressed as:

Where s is speed, d is distance and t is time taken.
We substitute our given distance into the equation

The average speed of the runner is 8.7m/s
Therefore, Option C) 8.7m/s is the correct answer.
Learn more: brainly.com/question/21503615
They both have a constant acceleration of g (9.8 m/s) So they both have equal accelerations. This is according to the law of gravity
Answer:
a) Total distance travelled = 1.9km + 8.7km + 3.0km = 13.6km
b) Total displacement = -1.9km + 8.7km-3.0km=+3.8km
Total displacement = 3.8km due west
Explanation:
a) Total distance travelled is a scalar quantity it is not affected by the direction it's only concerned with the magnitude.
Total distance travelled = 1.9km + 8.7km + 3.0km = 13.6km
b) Total displacement is a vector quantity it takes into consideration both magnitude and direction.
Taking west as positive and east as negative.
Total displacement = -1.9km + 8.7km-3.0km = +3.8km
Total displacement = 3.8km due west
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