A box mass of 24kg is being pulled horizontally on a rough surface by an applied force of 585N. The coefficient of kinetic frict
2 answers:
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(a) 0.714 cm
First of all, we need to find the spring constant of the spring. This can be done by using Hooke's law:
where
F is the force applied on the spring
k is the spring constant
x is the stretching of the spring
At the beginning, the force applied is the weight of the block of m = 4.20 kg hanging on the spring, therefore:
The stretching of the spring due to this force is
x = 2.00 cm = 0.02 m
Therefore, the spring constant is
Now, a new object of 1.50 kg is hanging on the spring instead of the previous one. So, the weight of this object is
And so, the stretching of th spring in this case is
(b) 1.65 J
The work done on a spring is given by:
where
k is the spring constant
x is the stretching of the spring
In this situation,
k = 2060 N/m
x = 4.00 cm = 0.04 m is the stretching due to the external agent
So, the work done is
Answer:
a)
b)
c)
Explanation:
Given:
distance between the fixed end of strings,
mass of string,
tension in the string,
a)
<u>Since the wave vibrating in the string is in third harmonic:</u>
Therefore wavelength λ of the string:
b)
We know that the velocity of the wave in this case is given by:
where:
linear mass density
<u>Now, frequency:</u>
c)
When the vibrations produce the sound of the same frequency:
Velocity of sound in air:
<u>Wavelength of the sound waves in air:</u>
Answer:
Explanation:
Let the race be of a fixed distance x
Troy's Average speed = 3 miles/hr = x / 0.2 hr
x = 0.6 miles
Abed's Average speed = 0.6 / 0.125 = 4.8 miles/hr