Suppose the initial position of an object is zero, the starting velocity is 3 m/s and the final velocity was 10 m/s. The object
moves with constant acceleration. Which part of a velocity vs. time graph can be used to calculate the displacement of the object? A. the area of the rectangle under the line B. the area of the rectangle above the line C. the area of the rectangle plus the area of the triangle under the line D. the area of the rectangle plus the area of the triangle above the line
2 answers:
Answer:
C. the area of the rectangle plus the area of the triangle under the line
Explanation:
Based on the information provided, the velocity vs. time graph is a line with a positive slope and a y-intercept of (0, 3). The displacement is the area under this line. This area can be divided into a triangle and a rectangle. So of the options available, C is the correct one.
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Answer:
69000 V
Explanation:
E = Electric field =
d = Distance between plates = 2.3 cm
When we multiply the electric field strength and the distance between the plates of a capacitor we get the maximum voltage.
Maximum voltage is given by
The highest voltage the students can use is 69000 V