The tensile stress of the wire supporting 2 kg mass is determined as 6.1 x 10⁷ N/m².
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Tensile stress of the wire</h3>
The tensile stress of the wire is calculated as follows;
σ = F/A
where;
A = πr² = πD²/4
where;
A = π x (0.64 x 10⁻³)²/4
A = 3.22 x 10⁻⁷ m²
σ = F/A = (mg)/A = (2 x 9.8)/( 3.22 x 10⁻⁷)
σ = 6.1 x 10⁷ N/m²
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The missing value is the 'k' that should appear between '28' and 'g' .
Nobody has a mass of 28g.
My new grandson, who was born yesterday (January 29, 2019), had a mass of 4,039g at birth.
Mother and son are happy and resting comfortably today, in Kfar Tapuach, Samaria, Israel.
I think that chalk is a compound. it is made up of molecules containing one calcium atom ,one carbon atom and three oxygen atoms.
<span>B?) Electric field E = q / (εo*A)
C) V = E*d = q*d / (εo*A)
D) V = q / C
so C = q / V = q * 1/V = q*εo*A / q*d = εo*A / d
I hope this helps! ^_^
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t = time of contact of hammer with the nail = 0.4 sec
I = impulse exerted by the hammer on the nail = 32 N s
F = force applied by the hammer on the nail
we know that , impulse is given as
I = F t where I = impulse , F = force , t = time
hence the impulse of hammer on nail is given as
I = F t
inserting the values
32 Ns = F (0.4 sec)
F = 32/0.4
F = 80 N
hence the force exerted by the hammer comes out to be 80 N
