A solution (in this experiment solution of NaNO₃) freezes at a lower temperature than does the pure solvent (deionized water). The higher the
solute concentration (sodium nitrate), freezing point depression of the solution will be greater.
Equation describing the change in freezing point:
ΔT = Kf · b · i.
ΔT - temperature change from pure solvent to solution.
Kf - the molal freezing point depression constant.
b - molality (moles of solute per kilogram of solvent).
i - Van’t Hoff Factor.
First measure freezing point of pure solvent (deionized water). Than make solutions of NaNO₃ with different molality and measure separately their freezing points. Use equation to calculate Kf.
Answer:
A) 0 °C, because it is the melting point of ice.
Explanation:
- Point B is the temperature at which the water is converted from ice (solid phase) to liquid water (liquid phase), which is the melting transition of water.
Melting point of the water is at 0.0°C.
<em>So, the right choice is: A) 0 °C, because it is the melting point of ice. </em>
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Independent and dependent variables and constants
Answer:
It is not a gas because its particles do not have large space between them.
Other predators? or other factors that affect the food chain ie extinction of whatever source the rabbits feed off of
