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Nikolay [14]
3 years ago
7

The famous clock tower in London has a minute hand that is 14 feet long. How far does the tip of the minute hand of Big Ben trav

el in 35 minutes?
Physics
2 answers:
Yanka [14]3 years ago
7 0
Think of the clock's face as a circle. You've been given the length of the minute hand: that tells you the radius of the circle. Use that to work out its circumference (I'm sure you already know the formula for that), then - as 35 minutes is seven-twelfths of 60 minutes - work out what seven-twelfths of that circumference is.<span>
</span>
Alex777 [14]3 years ago
5 0

Answer:

The tip of the minute hand of Big Ben travel in 35 minutes by 51.31 ft

Explanation:

Angle rotated by minute hand in 1 hour = 360⁰

Angle rotated by minute hand in 60 minutes = 360⁰

Angle rotated by minute hand in 1 minute = 6⁰

Angle rotated by minute hand in 35 minutes = 35 x 6 = 210⁰

Perimeter of 1 full circle = 2πr

Perimeter of 360⁰ circle = 2πr

\texttt{Perimeter of }210^0 \texttt{ arc =}2\pi r\times \frac{210}{360}

Here r = 14 feet

Substituting

\texttt{Perimeter of }210^0 \texttt{ arc =}2\pi \times 14\times \frac{210}{360}=51.31ft

The tip of the minute hand of Big Ben travel in 35 minutes by 51.31 ft

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Answer:

8m * (μg/v)^2

Explanation:

k, the spring constant = ?

(k in terms of μ, m, g, and v.)

Frictional force = μmg

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Cancel the 1/2 on both sides

mv^2 = μmgx + kx^2

Lets recall that:

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Therefore

1/2kx^2 = μmgx..... equation ii

Let's substitute 1/2kx^2 in equation I for ii

So we can say that:

1/2mv^2 = (μmgx)+ μmgx

1/2mv^2 = 2 (μmgx)

1/4mv^2 = μmgx

Cancel out m on both sides

1/4v^2 = μgx

Make x subject of the formula

x = (1/4v^2) / (μg)...... equation iii

substitute x to equation ii

But first make k in equation ii subject of the formula

1/2kx^2 = μmgx

k = 2μmg/x

Now substitute x

k = 2μmg / ((1/4v^2) / (μg))

k = 2μmg * ((μg) / (1/4v^2))

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2 years ago
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Natasha_Volkova [10]
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4 0
2 years ago
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2 years ago
Why is traveling between the stars (by creatures like us) difficult?
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Answer:

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4 0
3 years ago
Question 4 How much time does it take to walk 8 km north at a velocity of 3.8 km/h?​
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Given parameters:

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Unknown:

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The time taken is 2.1s

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