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irga5000 [103]
3 years ago
5

Raw data often appears in published scientific journals. Please select the best answer from the choices provided T F

Physics
2 answers:
joja [24]3 years ago
6 0

Answer: <u>The correct answer is False.</u>

Explanation: The term "raw data" refers to the data that has not been processed or "clean" for use. A scientific journal is a type of publication that specializes in publishing new researches of the scientific field. These researches contain information, that is considered the end product of processing the raw data. It is most likely that raw data would not be used as it comes in published scientific articles.

Hatshy [7]3 years ago
5 0

This statement is false

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The blackbody emission spectrum of object A peaks in the ultraviolet region of the electromagnetic spectrum at a wavelength of 2
seraphim [82]

Answer:

A) Object A is 3.25 times hotter.

B) Object A radiates 111.6 times more energy per unit of area.

Explanation:

Wiens's law states that there is an inverse relationship between the wavelength in which there is a peak in the emission of a black body and its temperature, mathematically,

\lambda_{peak}= \dfrac{0.0028976}{T},

where T is the temperature in kelvins and, \lambda_{peak} is the wavelenght (in meters) where the emission is in its peak.

From here, if we solve Wien's law for the temperature we get

T=\dfrac{0.0028976}{\lambda_{peak}}.

Now, we can easily compute the temperatures.

For object A:

T_{A}=\dfrac{0.0028976}{200*10^{-9}}

T_{A}=14488K.

For object B:

T_{B}=\dfrac{0.0028976}{650*10^{-9}}

T_{B}=4458K

From this, we get that

T_{A}/T_{B}=3.25,

which means that object A is 3.25 times hotter.

Stefan's Law states that a black body emits thermal radiation with power proportional to the fourth power of its temperature.

This is

E=\sigma T^{4},

where  \sigma=5.67*10^{-8}\ Wm^{-2}K^{-4} is call the Stefan-Boltzmann constant.

From this, power can be easily compute:

E_{A}=(5.67*10^{-8}*(14488)^{4})=2.5*10^{9}W\\E_{B}=(5.67*10^{-8}*(4458)^{4})=22.4*10^{6}}W,

and we can notice that

E_{A}/E_{B}=111.6,

which means that object A radiates 111.6 time more energy per unit of area.

8 0
3 years ago
The heat vaporization for methyl alcohol is 1100 kj/kg. It is 2257 KJ/Kg for water. Thus means that______________.
dusya [7]

Answer: B) Methyl alcohol requires less than half as much energy per kg to evaporate than water does

Explanation:

Latent heat of vaporization is the amount of heat required to convert 1 kilo gram of liquid into its vapor state without change in its temperature.

Heat of vaporization is more for water than for methyl alcohol which means more heat is required to convert from liquid to vapour form.

As the Heat of vaporization for methyl alcohol  (1100) is almost half as that of Heat of vaporization for water (2257) , it means  Methyl alcohol requires less than half as much energy per kg to evaporate than water does.

7 0
3 years ago
What happens to the compass needle as you move the compas<br> around the magnet?
Ugo [173]

Answer:

When you moved the compass near a bar magnet, the needle pointed toward the magnet's magnetic field and not toward the north.

Explanation:

4 0
3 years ago
A soccer ball is rolling across a soccer field. The system consists of the
neonofarm [45]

Answer:

NEGATIVE

Explanation:

5 0
3 years ago
Give reason standard physical quantity is used for correct measurement of the given body​
PtichkaEL [24]

Answer:

Physical quantities are the substances which can be measured. By measuring physical quantities, we can measure the mass, weight and other physical properties

4 0
3 years ago
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