We have no clue until we see the drawing. After all, the drawing shows its path.
Mechanical and Chemical. (Weathering and erosion)
The elastic potential energy stored in the stretched spring is 1 J.
<h3>What is Hooke's law?</h3>
Hooke's law states that; provided the elastic limit is not exceeded, the extension of the spring is directly proportional to the force on the spring.
Given that;
Force on the spring = 350 Newton
Distance stretched = 7 centimeters or 0.07 m
Hence;
F = ke
k = F/e = 350 Newton/0.07 m = 5000 N/m
Work done in stretching a spring = 1/2ke^2
= 0.5 × 5000 × (2 × 10^-2)^2 =1 J
Learn more about elastic potential energy: brainly.com/question/156316
Answer:
20 m
Explanation:
We'll begin by calculating the kinetic energy of the mass. This can be obtained as follow:
Mass (m) = 10 kg
Velocity (v) = 20 m/s
Kinetic energy (KE) =?
KE = ½mv²
KE = ½ × 10 × 20²
KE = 5 × 400
KE = 2000 J
Finally, we shall the height to which the mass must be located in order to have potential energy that is the same as the kinetic energy. This can be obtained as follow:
Mass (m) = 10 kg
Acceleration due to gravity (g) = 10 m/s²
Potential energy (PE) = Kinetic energy (KE) = 2000 J
Height (h) =..?
PE = mgh
2000 = 10 × 10 × h
2000 = 100 × h
Divide both side by 100
h = 2000 / 100
h = 20 m
Thus, the object must be located at a height of 20 m in order to have potential energy that is the same as the kinetic energy.
Answer:
132 N
Explanation:
Given that a 1.1 kg hammer strikes a nail. Before the impact, the hammer is moving at 4.5 m/s; after the impact it is moving at 1.5 m/s in the opposite direction. If the hammer is in contact with the nail for 0.025 s, what is the magnitude of the average force exerted by the hammer on the nail
From Newton 2nd law of motion,
Change in momentum = impulse.
Change in momentum = m( V - U )
Substitute all the parameters into the formula
Change in momentum = 1.1 ( 4.5 - 1.5 )
Change in momentum = 1.1 × 3
Change in momentum = 3.3 kgm/s
Impulse = Ft
That is,
Ft = 3.3
Substitute time t into the formula above
F × 0.025 = 3.3
F = 3.3 / 0.025
F = 132 N
Therefore, the magnitude of the average force exerted by the hammer on the nail is 132 N.
