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3 years ago

Which tool do we use to measure wind

Physics

2 answers:

wariber [46]3 years ago

8 0

Answer:

windmill anemometer

Explanation:

windmill anemometer is commonly used by news stations to measure winds speeds

svetlana [45]3 years ago

5 0

Answer:

windmill anemometer

Explanation:

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Ted throws an object straight up into the air with an initial velocity of 54 ft/s from a platform that is 40 ft above the ground

elena-s [515]

Answer:

The time it will take for the object to hit the ground will be 4.

Explanation:

You have:

h(t)=−16t²+v0*t+h0

Being v0 the initial velocity (54 ft/s) and h0 the initial height (40 ft) and replacing you get:

h(t)=−16t²+54*t+40

To know how long it will take for the object to touch the ground, the height h(t) must be zero. So:

0=−16t²+54*t+40

Being a quadratic function or parabola: f (x) = a*x² + b*x + c, the roots or zeros of the quadratic function are those values of x for which the expression is 0. Graphically, the roots correspond to the points where the parabola intersects the x axis. To calculate the roots the expression is used:

$\frac{-b+-\sqrt{b^{2}-4*a*c } }{2*a}$

In this case you have that:

a=-16
b= 54
c= 40

Replacing in the expression of the calculation of roots you get:

$\frac{-54+\sqrt{54^{2}-4*(-16)*40 } }{2*(-16)}$ Expresion (A)

and

$\frac{-54-\sqrt{54^{2}-4*(-16)*40 } }{2*(-16)}$ Expresion (B)

Solving the Expresion (A):

$\frac{-54+\sqrt{5476 } }{2*(-16)}= \frac{-54+74}{2*(-16)}=\frac{20}{2*(-16)}=\frac{20}{-32}= -\frac{5}{8}$

Solving the Expresion (B):

$\frac{-54-\sqrt{5476 } }{2*(-16)}= \frac{-54-74}{2*(-16)}=\frac{-128}{2*(-16)}=\frac{-128}{-32}= 4$

These results indicate the time it will take for the object to hit the ground can be -5/8 and 4. Since the time cannot be negative, then <u><em>the time it will take for the object to hit the ground will be 4.</em></u>

6 0

3 years ago

A 10 kg frictionless cart is pushed at a constant force of 5.0 N for a distance of 10 m. The work done on the cart is 50J.

kykrilka [37]

1) Final kinetic energy of the cart: B) 50 J

2) Final speed of the cart: C) 3.2 m/s

3) Height reached along the ramp: A) 0.5 m

Explanation:

We can solve this part of the problem by using the work-energy theorem, which states that the work done on an object is equal to the kinetic energy gained by the object itself. Mathematically:

$W=K_f - K_i$

where

W is the work done

$K_f$ is the final kinetic energy

$K_i$ is the initial kinetic energy

In this problem, the work done on the cart is

W = 50 J

And assuming it starts from rest, its initial kinetic energy is zero:

$K_i = 0$

Therefore, the final kinetic energy is:

$K_f = K_i + W=0+50=50 J$

The kinetic energy of an object is the energy possessed by an object due to its motion; it is calculated as

$K=\frac{1}{2}mv^2$

where

m is the mass of the object

v is its speed

For the cart in this problem, we have:

K = 50 J is its final kinetic energy

m = 10 kg is the cart

Therefore, solving the formula for v, we find its speed:

$v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(50)}{10}}=3.2 m/s$

We can think this problem in terms of conservation of energy. In fact, as the cart rolls up the ramp, its kinetic energy is converted into gravitational potential energy, which is given by

$PE=mgh$

where

m is the mass

$g=9.8 m/s^2$ is the acceleration of gravity

h is the heigth of the cart

When the cart reaches the maximum height, all the kinetic energy has been converted into potential energy, so we can write:

$K=PE\\\frac{1}{2}mv^2=mgh$

Re-arranging,

$h=\frac{v^2}{2g}$

And since we know the initial speed of the cart along the ramp,

v = 3.2 m/s

we can find the maximum height reached along the ramp:

$h=\frac{3.2^2}{2(9.8)}=0.5 m$

Learn more about work, kinetic energy and potential energy:

brainly.com/question/6763771

brainly.com/question/6443626

brainly.com/question/6536722

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

7 0

3 years ago

The electric current in a wire is 1.5A. How many electrons flow past a given point in a time of 2s?

kipiarov [429]

Answer:

The amount of electrons that flow in the given time is 3.0 C.

Explanation:

An electric current is defined as the ratio of the quantity of charge flowing through a conductor to the time taken.

i.e I = $\frac{Q}{t}$ ...................(1)

It is measure in Amperes and can be measured in the laboratory by the use of an ammeter.

In the given question, I = 1.5A, t = 2s, find Q.

From equation 1,

Q = I × t

= 1.5 × 2

= 3.0 Coulombs

The amount of electrons that flow in the given time is 3.0 C.

5 0

3 years ago

Explain the expression “light travels at a speed”.

Anestetic [448]

Some things travel faster than the speed of light

7 0

3 years ago

When a circuit is arranged in parallel

attashe74 [19]

Answer:

A. There are multiple paths that electrons can take through the circuit, and it is possible for the electron to pass through one circuit component but not another.

Explanation:

Parallel arrangement of components in an electric circuit puts different parts of the circuit on different branches. In a parallel connection, there are multiple paths for the electrons to take, and it is possible for electrons to pass through on circuit component without going through another. This is the reason why If there is a break in one branch of the circuit, electrons can still flow in other branches, and the same reason why one bulb going off in your home does prevent the other components in your home from coming on (your home is wired in a parallel electric circuit).

5 0

3 years ago