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3 years ago

The visible spectrum refers to the portion of the electromagnetic spectrum that we ________.

Physics

1 answer:

yKpoI14uk [10]3 years ago

8 0

<h2>Answer: can see</h2>

Explanation:

The portion visible by the human eye of the electromagnetic spectrum is between 380 nm (violet-blue) and 780 nm (red) approximately. Which means this part of the spectrum is located between ultraviolet light and infrared light.

Note the fact only part of the whole electromagnetic spectrum is visible to humans is because the receptors in our eyes are only sensitive to these wavelengths.

Therefore:

<h2>The visible spectrum refers to the portion of the electromagnetic spectrum that <u>we </u><u>can see</u></h2>

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TRUE OR FALSE??

Stels [109]

Answer:

false, true, true, true, false

Explanation:

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3 years ago

What is NOT a raw minteral used in photosyntheisis

Yuliya22 [10]

The photosynthesis equation is :

H2O + CO2 + sunlight (energy) > C6H12O6 + O2

So water (H2O) and carbon dioxide (CO2) are the raw materials need for photosynthesis.

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4 years ago

an athlete is running at a constant velocity with a javelin held in his right hand.the force he is applying on thejavelin as he

mestny [16]

50 Nm
work=force*change in position

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3 years ago

Two moles of an ideal monatomic gas go through the cycle abc. For the complete cycle, 800 J of heat flows out of the gas. Proces

KiRa [710]

a) Sketches of all possible pv-diagrams for the cycle are attached below

b) The work W $_{ac}$ for the process Ca is : 2462.8 J

<u>Given data :</u>

Amount of heat flowing out = 800 J

Ta = 200 K

Tb = 300 K

R = 800

<u>B) Determine the </u><u>work W </u><u>for the process</u><u> Ca</u><u> </u>

Wₐs = -pdv

= - [ pVb - pVa ] ---- ( 1 )

note : pVb = nRTb , pVa = nRTa

Equation ( 1 ) becomes

= -nR [ Tb - Ta ]

= - 2(8.314 ) [ 300 - 200 ]

= - 1662.87

given that W $_{bs}$ = 0 which is isochonic

dv = 0 ( cyclic process ) = d∅ - dw

∴ 0 = 800 - ( Wₐs + W $_{ac}$ )

Therefore : W $_{ac}$ = 800 + 1662.8 = 2462.8 J

Hence we can conclude that the work W for the process Ca = 2462.8 J

Learn more about Pv diagrams : brainly.com/question/25401637

Download pdf

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3 years ago

In a certain oscillating LC circuit, the total energy is converted from electrical energy in the capacitor to magnetic energy in

aleksandrvk [35]

Answer:

A = 5.6μs

B = 178.57kHz

C = 2.8μs

Explanation:

A. It takes ¼ of the period of the circuit before the total energy is converted from electrical energy in the capacitor to magnetic energy in the inductor.

t = T/4

T = 4*t

T = 4 * 1.4 = 5.6μs

B. f = 1/T

Frequency is the inverse of period

f = 1 / 5.6*10⁻⁶

f = 178571.4286Hz

f = 178.57kHz

C. time taken for maximum energy to occur is T/2

t = 5.6 / 2 = 2.8μs

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3 years ago