All categories

4 years ago

A _____ is used in a motor to switch the direction of the magnetic field created by the current.

Physics

1 answer:

insens350 [35]4 years ago

8 0

Answer:

A _commutator_ is used in a motor to switch the direction of the magnetic field created by the current.

The rotating part of a motor that holds the electromagnets is called the __armature___.

Electric current passes through the _brushes_ and into the electromagnets in an electric motor.

A motor turns _electrical_ energy into _mechanical_ energy.

Explanation:

A commutator, which is a split ring rotary switching device, reverses the direction of the current between the external circuit and the rotor. Reversing the current reverses the magnetic field.

The armature comprises the rotating part of the motor and the electromagnets

A brush is the electrical contact for conducting current through the moving and stationary parts of an electric motor

An electric motor turns electrical energy into mechanical energy.

You might be interested in

A Dodge Stealth is driving at 70 mph on a highway. It passes a BMW going the same direction. The BMW is moving 7 mph backward re

Tasya [4]

A Dodge Stealth is driving at 70 mph on a highway. It passes a BMW going the same direction. The BMW is moving 7 mph backward relative the Dodge. 63 mph is the velocity of the BMW

Answer: Option A

<u>Explanation:</u>

Given is the speed of the dodge stealth as 70 mph passing by the BMW moving with 7 mph relative to Dodge. Thereby, to calculate the velocity of BMW, relative velocity concept has to be employed.

As we know that the relative velocity tells us about relative velocity of mobile reference system as the difference or sum of the initial reference system.

Therefore,

velocity of the BMW = $v_{b}$

Velocity of the dodge = $v_{d}$

Velocity of the BMW with respect to dodge = $V_{b d}$

As per the formula,

$v_{b d}=v_{b}-v_{d}$

$v_{b} = v_{d} + v_{b d} = 70 + (-7) = 70 - 7 = 63 \mathrm{mph}$

5 0

3 years ago

The energy of a wave is directly proportional to the square of the ___. D.Amplitude c. crest b. wavelength a.frequency

IRISSAK [1]

The energy of a wave is directly proportional to the square of the D.Amplitude

the energy of a wave is given as

E = (0.5) (μ v t ) w² A²

where t = time

μ = mass per unit length of the string

v = wave propagation of velocity.

w = angular frequency

A = amplitude

E = energy of wave

From the equation , we see that

the energy of wave "E" is directly proportional to A².

hence the correct choice is D. Amplitude.

4 0

3 years ago

Which describes one event that causes an eclipse?

seraphim [82]

Answer:

earth's shadow covering the moon,thats lunar eclipse

5 0

4 years ago

Fifty grams of ice at 0◦ C is placed in a thermos bottle containing one hundred grams of water

Sloan [31]

Answer:

7.55 g

Explanation:

Heat of fusion = 333kj/kg

Heat capacity, c = 4190 j/kg /k

Heat capacity in j/g /k = 0.4190

Let the Number of grams of ice that will melt = n

Number of grams * heat of fusion = heat capacity * temperature change

n * 0.333 = 0.419 * (6-0)

0.333n = 2.514

n = 2.514 / 0.333

n = 7.5495

n = 7.55 gram

Hence, the number of gram of ice that will melt is 7.55 grams

5 0

3 years ago

Monochromatic light with a wavelength of 6.4 E -7 meter passes through two narrow slits, producing an interference pattern on a

seropon [69]

Answer:

The distance between the slits is given by 1.3 × $10^{-4}$ m

Given:

$\lambda = 6.4 \times 10^{-7} m$

D = 4 m

y = $2 \times 10^{-2} m$

m = 1

To find:

distance between slits, d = ?

Formula used:

y = $\frac{m \times \lambda \times D}{d}$

y = distance of first bright band from central maxima

D = distance between screen and source

d = distance between slits

$\lambda$ = wavelength

Solution:

distance of first bright band from central maxima is given by,

y = $\frac{m \times \lambda \times D}{d}$

y = distance of first bright band from central maxima

D = distance between screen and source

d = distance between slits

$\lambda$ = wavelength

Thus,

d = $\frac{m \times \lambda \times D}{y}$

d = $\frac{1 \times 6.4 \times 10^{-7} \times 4 }{2 \times 10^{-2} }$

d = 1.28 × $10^{-4}$

d = 1.3 × $10^{-4}$ m

The distance between the slits is given by 1.3 × $10^{-4}$ m

8 0

3 years ago