Answer:
I think the 1st statement is right.
Explanation:
Wind patterns doesn't stay the same.
Waves don't follow the same patterns.
Waves move further up the shore.
I didn't hear about "waves adding" before..so i guess 1st statement is right.
Answer:
Explanation:
The momentum of the first piece = m v =- m x 31 i kg m/s in - x direction direction
The momentum of the second piece = -m x 31 j kg m /s in Y - direction
Total momentum = - 31 m( i + j )
To conserve momentum , the third piece must have momentum equal to this
and opposite to it
So momentum of the third piece = 3m x V = 31 m ( i +j )
V = 31/3 ( i + j ) =
Magnitude of velocity V = √2 x 31/ 3 = 14.6 m / s
Its direction will be towards the vector i + j ie 45° from x - axis in positive direction
Answer:
300J
Explanation:
Work done = Force x the distance travelled in the direction of the force
=300 x 1
=300J
The answer to your question would be A. infrared light
Answer:
It takes <em>40 hours</em> to melt the block of ice.
Explanation:
According to the principles of radiation and heat transfer respectively:
<em>ΔQ = I(dt)eAcosθ </em>(I = Solar energy density; dt = time taken; e = emissivity; A = Area of block; θ = angle between the sun ray and the horizontal)
<em>ΔQ = mLf</em> (ΔQ = Heat change; m = mass of ice; Lf = Specific latent heat of fusion of ice)
but m = ρV = ρ.A.<em>d</em>x, therefore, the heat transfer equation can be re-written as:
<em>ΔQ = ρ.A.dx.Lf</em>
Lets equate the radiation equation and the modified heat transfer equation, we have:
<em>ρ.A.dx.Lf = I(dt)eAcosθ</em>
<em>ρ.dx.Lf = I(dt)ecosθ </em>(Striking out the area)
Let's make <em>dt</em> the subject of formula,
dt = ρ.dx.Lf /I.e.cosθ
ρ = Density of ice, 
Lf = 
e = 0.050
θ = 32 deg. C
Now, let's substitute the terms:


Therefore, the time taken for the ice to completely melt is <em>40 hours</em> (Two significant figures)