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Svetllana [295]
4 years ago
5

Advantages of hubble law

Physics
1 answer:
Tatiana [17]4 years ago
7 0
The first huge advantage of the Hubble law is the ability to see objects without the obscuration of the atmosphere, the atmosphere distorts and obscures a great deal of light from distant and dim objects. By placing the telescope outside the atmosphere this problem is eliminated, also the Hubble being space based can observe phenomena that might be completely missed by land based telescopes because they occur during daylight hours at the land based location. There is no daytime obscuration of the stars from space.
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You are holding a finishing sander with your right hand. THe sander has a flywheel which spins counterclockwise as seen from beh
ryzh [129]

Answer:

c. turn downward

Explanation:

From the information given:

To find the tendency of the sander;

We need to apply the right-hand rule torque; whereby we consider the direction of the flywheel, the direction at which the torque is acting, and the movement of the sander toward the right.

Since the flywheel of the sander is in counterclockwise movement, hence the torque direction will be outward placing on the wall. However, provided that the movement of the sander is toward the right, then there exists an opposite force that turns downward which showcases the tendency in the sander is downward.

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3 years ago
1 a rectangular block of steel measures 4cm * 2cm* 1.5cm. its mass is 93 .6g
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4 years ago
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What is the gravitational force on a 10 kg sled traveling at 3.5 m/s down a track?
Jobisdone [24]
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8 0
4 years ago
Bare free charges do not remain stationary when close together. To illustrate this, calculate the acceleration of two isolated p
Marta_Voda [28]

Answer:

Acceleration, a=9.91\times 10^{15}\ m/s^2

Explanation:

It is given that,

Separation between the protons, r=3.73\ nm=3.73\times 10^{-9}\ m

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Mass of protons, m=1.67\times 10^{-27}\ kg

We need to find the acceleration of two isolated protons. It can be calculated by equating electric force between protons and force due to motion as :

ma=\dfrac{kq^2}{r^2}

a=\dfrac{kq^2}{mr^2}      

a=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{1.67\times 10^{-27}\times (3.73\times 10^{-9})^2}      

a=9.91\times 10^{15}\ m/s^2

So, the acceleration of two isolated protons is 9.91\times 10^{15}\ m/s^2. Hence, this is the required solution.

3 0
3 years ago
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