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WINSTONCH [101]
3 years ago
7

Atrial natriuretic peptide is a hormone that controls blood pressure in part by increasing the urinary excretion of sodium. True

or False
Chemistry
1 answer:
mariarad [96]3 years ago
4 0

Answer:

The answer is "true"

Explanation:

ANP, or ANF, is a human peptide hormone, that controls your blood pressure, a cardiac atrium secretion hormone. It response primarily to the volume and stress expansion of the auricles and ventricles.

  • ANP's main function decreases the amount of increased extracellular fluid by increasing renal excretion.
  • This hormone is primarily developed by cardiovascular myocytes and, emanates from the wall tension locally, that's why the given statement is true.

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A technical machinist is asked to build a cubical steel tank that will hold 195 L of water. Calculate in meters the smallest pos
Aleks04 [339]

Answer:

The smallest possible inside length of the tank is 0.579 m.

Explanation:

As we know that

1 m^3 = 1000 L

Thus, volume of 195 liter tank is also equal to 0.195 cubic meter

The volume of a cube is equal to x^3, where, x is the length of the side of the cube

With the give condition,

x^ 3 = 0.195

Solving the above equation, we get -

x = (0.195)^{\frac{1}{3})}\\x = 0.579

The smallest possible inside length of the tank is 0.579 m.

4 0
3 years ago
Consider the reaction between hydrazine and hydrogen to produce ammonia, N2H4(g)+H2(g)→2NH3(g). Use enthalpies of formation and
kupik [55]

Answer:

The enthalpy of the nitrogen-nitrogen bond in N2H4 is 162.6 kJ

Explanation:

For the reaction: N2H4(g)+H2(g)→2NH3(g), the enthalpy change of reaction is

ΔH rxn = 2 ΔHºf NH3 - ΔHºf N2H4

but we also know that the ΔH rxn is calculated by accounting   the sum of number of bonds formed and bonds broken as follows:

ΔH rxn = 6H (N-H) + 4 (N-H) + 2H (H-H)  

where H is the bond enthalpy .When bonds are broken H is positive, and negative when formed,  in the product there are 6 N-H bonds , and in the reactants 4 N-H and 1 H-H bonds).

Consulting an appropiate reference handbook or table the following values are used:

ΔHºf (NH3) = -46 kJ/mol

ΔHºf (N2H4) = 95.94 kJ/mol

(The enthalpy of fomation of hydrogen in its standard state is zero)

H (N-H) = 391 kJ

H (H-H) = 432 kJ

H (N-N) = ?

So plugging our values:

ΔH rxn =  2mol ( -46.0 kJ/mol) - 1mol(95.4 kJ/mol) = -187.40 kJ

-187.40 kJ = 6(-391 kJ) + 4 (391 kJ) + 432 +  H(N-N)

-187.40 kJ = -350 kJ + H(N-N)

H(N-N) = 162.6 kJ

7 0
3 years ago
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