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horrorfan [7]
3 years ago
10

Write the formula for potassium oxide. why do you not need prefixes in the name ​

Chemistry
1 answer:
Molodets [167]3 years ago
7 0

Potassium oxide: K₂O.

There's no need for prefixes since K₂O is an ionic compound.

<h3>Explanation</h3>

Find the two elements on a periodic table:

  • Potassium- K- on the left end of period four.
  • Oxygen- O- near the right end of periodic two.

Elements on the bottom-left corner of the periodic table are metals. Those on the top-right corner are nonmetals.

  • Potassium is a metal,
  • Oxygen is a nonmetal.

A metal and a nonmetal combine to form an ionic compound. Potassium oxide is likely to be an ionic compound. It contains two types of ions:

  • Potassium ions: Potassium is group 1 of the periodic table. It is an alkaline metal. Like other alkaline metals such as sodium Na, potassium K tends to lose one electron and form ions of charge +1 in compounds. The ion would be K⁺.
  • Oxide ions from oxygen: Oxygen is the second most electronegative element on the periodic table. It tends to gain two electrons and form the oxide ion \text{O}^{2-} when it combines with metals.

The two types of ions carry opposite charges. They shall pair up at a certain ratio such that they balance the charge on each other. The charge on each \text{O}^{2-} ion is twice that on a \text{K}^{+} ion. Each \text{K}^{+} would pair up with two \text{O}^{2-}. Hence the subscript in the formula: \text{K}_{\bf 2}\text{O}.

There are two classes of compounds:

  • Covalent compounds, which need prefixes, and
  • Ionic compounds, which need no prefix.

Prefixes are needed only in covalent compounds. For instance in the covalent compound carbon dioxide \text{CO}_2, the prefix di- indicates that there are two oxygen atoms in the formula \text{CO}_2. However, there's no need for prefix in ionic compounds such as \text{K}_2\text{O}.

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What is the mole, and why is it useful in chemistry?
Snowcat [4.5K]

Answer:The mole is important because it allows chemists to work with the subatomic world with macro world units and amounts. Atoms, molecules and formula units are very small and very difficult to work with usually. However, the mole allows a chemist to work with amounts large enough to use.

Explanation:

6 0
3 years ago
Which type of rock forms as a result of cooling and crystallization?
Dovator [93]

Answer:

Igneous rock is the type of rock that forms as a result of cooling an crystallization

Explanation:

  • Rocks are either sedimentary, igneous or metamorphic based on the chemical composition and the mode of formation.
  • Igneous rocks are formed as a result of the cooling and crystallization of magma from volcanic eruptions.
  • Igneous rocks are either intrusive, which form deep in the crust or extrusive which form on the surface of the earth.
  • Sedimentary rocks are formed as a result of deposition, and cementation of sediments.
  • Metamorphic rocks, on the other hand, are formed from the sedimentary and igneous rocks during the rock cycle.

7 0
3 years ago
Which of the following shows 3x + 15 + 6x – 7 + y in simplest terms?
prisoha [69]

Answer:

9x+y+8

Explanation:

We know this because you add 3x and 6x to get 9x

then we only have one y so put y by itself then subtract 15 and y which gets us 8

3 0
3 years ago
Which of the following electron transitions in a hydrogen atom emits light of the shortest wavelength? Circle the correct answer
Lilit [14]

Answer:

Transition from n = 4 to n = 1  corresponds to shortest wavelength.

Explanation:

         Process                   \mid \Delta n\mid =\mid \frac{1}{(n)_{final}^{2}}-(\frac{1}{n_{initial}^{2}})\mid

             A                                         0.9375

             B                                          0.75

             C                                          0.0421

             D                                          0.1875

According to Rydberg equation for electronic transition in H-like atoms:

           \frac{1}{\lambda }=R_{H}\mid (\frac{1}{n_{final}^{2}}-(\frac{1}{n_{initial}^{2}})\mid

where, \lambda is wavelength of light emitted or absorbed, R_{H} is Rydberg constant.

So, higher the value of \mid \Delta n\mid, lower will the corresponding wavelength of light.

Hence process A will be associated with shortest wavelength.

4 0
3 years ago
At 25°c, e° = +1.88 v for a cell based on the reaction 3 agcl(s) + al(s) → 3 ag(s) + al3+(aq) + 3 cl-(aq). find the cell potenti
Phantasy [73]
Use the Nernst equation which is:

E = E° - (RT/nF)*Ln Q 

Where:

E the cell voltage in V,

R the gas constant 8.314 J/K•mol,

T the room temperature normally taken 298.15K, n=3 in this case,

F the Faraday constant 96485C,

Ln is the operation of natural logarithm, and: Q = [Cl-]^3*[Al3+] 


Plugging in our values, will give us: 

E = 1.88-(8.314*298.15/(3*96485))*Ln(0.010^3...)

= 2.01 (V)
5 0
3 years ago
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