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3 years ago

Are those correct if not tell me which are wrong I need help with number 21 also

Chemistry

2 answers:

adelina 88 [10]3 years ago

3 0

For 23., you have to find a way to measure your heart rate not increase it. search it up on google.

aniked [119]3 years ago

3 0

For number 21, all you have to do is look at the bar graph and put the answer into a unit rate to make it easier

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Explanation:

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3 years ago

If 20.0 g of NaOH is added to 0.750 L of 1.00 M Cd(NO₃)₂, how many grams of Cd(OH)₂ will be formed in the following precipitatio

bulgar [2K]

Answer:

$m_{Cd(OH)_2}=36.6 gCd(OH)_2$

Explanation:

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In this case, for the given chemical reaction, in order to compute the grams of cadmium hydroxide that would be yielded, we must first identify the limiting reactant by computing the yielded moles of that same product, by 20.0 grams of NaOH (molar mass = 40 g/mol) and by 0.750 L of the 1.00-M solution of cadmium nitrate as shown below considering the 1:2:1 mole ratios respectively:

$n_{Cd(OH)_2}^{by\ NaOH}=20.0gNaOH*\frac{1molNaOH}{40gNaOH} *\frac{1molCd(OH)_2}{2molNaOH} =0.25molCd(OH)_2\\\\n_{Cd(OH)_2}^{by\ Cd(NO_3)_2}=0.750L*1.00\frac{molCd(NO_3)_2}{L}*\frac{1molCd(OH)_2}{1molCd(NO_3)_2} =0.75molCd(OH)_2$

Thus, since 20.0 grams of NaOH yielded less of moles of cadmium hydroxide, NaOH is the limiting reactant, therefore the mass of cadmium hydroxide (molar mass = 146.4 g/mol) is:

$m_{Cd(OH)_2}=0.25molCd(OH)_2*\frac{146.4gCd(OH)_2}{1molCd(OH)_2} \\\\m_{Cd(OH)_2}=36.6 gCd(OH)_2$

Best regards.

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3 years ago

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Vitek1552 [10]

Answer:

Explanation:

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3 years ago

To identify a diatomic gas (X2), a researcher carried out the following experiment: She weighed an empty 2.2-L bulb, then filled

Ber [7]

Answer:

Explanation:

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Given:

P = 2atm

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T = 27 degrees Celsius = 27 + 273.15 = 300.15K

V = 2.2L

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PV = nRT

Rearranging n = PV/RT

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This is the closest to the molar mass of diatomic nitrogen N2.

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3 years ago