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4 years ago

What is the momentum of a car with a mass of 1,300 kg traveling at a speed of 28 m/s?

Physics

1 answer:

Vlad1618 [11]4 years ago

7 0

Answer:

<h3>The answer is 36,400 kgm/s</h3>

Explanation:

The momentum of an object can be found by using the formula

<h3>momentum = mass × velocity</h3>

From the question

mass = 1,300 kg

speed / velocity = 28 m/s

We have

momentum = 1,300 × 28

We have the final answer as

Hope this helps you

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Two moving objects collide and move apart on paths 90 degrees apart. The total momentum after the collision is _______ the total

Tom [10]

A is the correct answer

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3 years ago

What does it mean when something says Expert Verified?<br><br> I am Marking brainliest!

alisha [4.7K]

Answer:

it means an expert verified the answer so its nearly always true

Explanation:

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3 years ago

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NASA is designing a mission to explore Titan, the largest moon of Saturn. Titan has numerous hydrocarbon lakes containing a mix

Vitek1552 [10]

Answer:

Total pressure in atmosphere IS 4.36 atm

Explanation:

Given Data:

Depth of lake is 400 mtr

surface tension is 147 kilopascals

surface temperature 94 kelvin

Gravity = 1.35 m/s^2

specific gravity of methane(liquid) = 0.415

specific gravity of ethane(liquid) = 0.546

density of methane can be obtained as

$\rho_{methane} = 0.415\times 1000 = 415 kg/m^3$

Density of ethane can be obtained as

$\rho_{ethane} = 0.546\times 1000 = 546 kg/m^3$

Total pressure in atmosphere can be obtained as

$P = surface\ tension + \rho_{max}gh$

$= 147 +546\times 1.35\times 400\times 10^{-3}$

= 441.84 kPa

$= 441.84\times 0.009869 atm\kPa$

= 4.36 atm

7 0

3 years ago

How much force is required to move a electron through an electric field with strength of 1.375 x 10^19 N/C?

Luda [366]

Answer:

The magnitude of the force required to move the electron through the given field is 2.203 N

Explanation:

Given;

The field strength of the electron, E = 1.375 x 10¹⁹ N/C

charge of electron, q = 1.602 x 10⁻¹⁹ C

The magnitude of the force required to move the electron through the given field is calculated as follows;

F = Eq

F = (1.375 x 10¹⁹ N/C) (1.602 x 10⁻¹⁹ C)

F = 2.203 N

Therefore, the magnitude of the force required to move the electron through the given field is 2.203 N

4 0

3 years ago

Find the cube roots of 27(cos 327° + i sin 327° ). Write the answer in trigonometric form.

Sati [7]

Answer:

$z^{\frac{1}{3} }= -0.978 + i\cdot 2.836$ , $z^{\frac{1}{3} }= -1.967 - i\cdot 2.265$ , $z^{\frac{1}{3} }= 2.945 - i\cdot 0.571$

Explanation:

The cube root of the complex number can determined by the following De Moivre's Formula:

$z^{\frac{1}{n} } = r^{\frac{1}{n} }\cdot \left[\cos\left(\frac{x + 2\pi\cdot k}{n} \right) + i\cdot \sin\left(\frac{x+2\pi\cdot k}{n} \right)\right]$

Where angles are measured in radians and k represents an integer between $0$ and $n - 1$ .

The magnitude of the complex number is $27$ and the equivalent angular value is $1.817\pi$ . The set of cubic roots are, respectively:

k = 0

$z^{\frac{1}{3} } = 3\cdot \left[\cos \left(\frac{1.817\pi}{3} \right)+i\cdot \sin\left(\frac{1.817\pi}{3} \right)]$

$z^{\frac{1}{3} }= -0.978 + i\cdot 2.836$

k = 1

$z^{\frac{1}{3} } = 3\cdot \left[\cos \left(\frac{3.817\pi}{3} \right)+i\cdot \sin\left(\frac{3.817\pi}{3} \right)]$

$z^{\frac{1}{3} }= -1.967 - i\cdot 2.265$

k = 2

$z^{\frac{1}{3} } = 3\cdot \left[\cos \left(\frac{5.817\pi}{3} \right)+i\cdot \sin\left(\frac{5.817\pi}{3} \right)]$

$z^{\frac{1}{3} }= 2.945 - i\cdot 0.571$

5 0

3 years ago