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Karolina [17]
3 years ago
5

What is the momentum of a car with a mass of 1,300 kg traveling at a speed of 28 m/s?

Physics
1 answer:
Vlad1618 [11]3 years ago
7 0

Answer:

<h3>The answer is 36,400 kgm/s</h3>

Explanation:

The momentum of an object can be found by using the formula

<h3>momentum = mass × velocity</h3>

From the question

mass = 1,300 kg

speed / velocity = 28 m/s

We have

momentum = 1,300 × 28

We have the final answer as

<h3>36,400 kgm/s</h3>

Hope this helps you

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disa [49]

Answer:

I =  26.36 cosω t A

Explanation:

Given that

C=0.74 mF

Vrms= 82 V

Frequency ,f= 49 Hz

We know that ω = 2 π f

ω = 2 x  π x 49

ω = 307.72 rad/s

As we know that voltage given as

V= Vo sinω t

V_o=\sqrt2\ V_{rms}

V_o=\sqrt2\ \times 82\

Vo=115.96 V

V=115.96 sinω t

The current given as

I=C\dfrac{dV}{dt}

I=0.74\times \dfrac{dV}{dt}\ mA

\dfrac{dV}{dt}=115.96\omega cos\omega t

I=0.74\times 115.96\times 307.22 cos\omega t\ mA

I = 26362.67 cosω t mA

I =  26.36 cosω t A

This is the current at time ant time t.

7 0
3 years ago
Under what condition is the instantaneous acceleration of a moving body equal to its average acceleration over time?
Rzqust [24]
If the acceleration is constant (negative or positive) the instantaneous acceleration cannot be

Average acceleration: [final velocity - initial velocity ] /Δ time

Instantaneous acceleration = d V / dt =slope of the velocity vs t graph

If acceleration is increasing, the slope of the curve at one moment will be higher than the average acceleration.

If acceleration is decreasing, the slope of the curve at one moment will be lower than the average acceleration.

If acceleration is constant, the acceleration at any moment is the same, then only at constant accelerations, the instantaneuos acceleration is the same than the average acceleration.

Constant zero acceleration is a particular case of constant acceleration, so at constant zero acceleration  the instantaneous accelerations is the same than the average acceleration: zero. But, it is not true that only at zero acceleration the instantaneous acceleration is equal than the average acceleration.

That is why the only true option and the answer  is the option D. only at constant accelerations.
3 0
3 years ago
Calculate the KE of a car which has a mass of 1000 kg and is moving at the rate of 20 m/s
Elan Coil [88]

Answer:

The kinetic energy of the car is 2.0\cdot 10^5 J

Explanation:

3 0
2 years ago
Chegg Given that the mean radius of the Moon’s orbit is 3.84 x 108 m and its period is 2.36 x 106 sec, at what altitude above th
alukav5142 [94]

Answer:

The altitude of geostationary satellite is 3.58\times10^{7}\ m

Explanation:

Given that,

Radius of moon's orbit r=3.84\times10^{8}\ m

Time period T=2.36\times10^{6}\ sec

We need to calculate the orbital radius of geostationary satellite is

Using formula of time period

T=\sqrt{\dfrac{4\pi^2}{GM}a^3}

a=((\dfrac{GM}{4\pi^2})T^2)^{\dfrac{1}{3}}

Where, G = gravitational constant

M = Mass of earth

T = time period of geostationary satellite orbit

Put the value in to the formula

a=((\dfrac{6.67\times10^{-11}\times5.97\times10^{24}}{4\times\pi^2})\times(86160)^2)^{\dfrac{1}{3}}

a=4.217\times10^{7}\ m

We need to calculate the altitude of geostationary satellite

Using formula of altitude

h = a-R_{e}

Where, R = radius of earth

a = radius of geostationary satellite

Put the value into the formula

h =4.217\times10^{7}-6.38\times10^{6}

h =35790000\ m

h=3.58\times10^{7}\ m

Hence, The altitude of geostationary satellite is 3.58\times10^{7}\ m

4 0
3 years ago
If the weight of displaced liquid and the weight of an object are the same, the object will:
liberstina [14]

Answer:

c

Explanation:

I think but if I'm wrong I'm sorry

8 0
3 years ago
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