What is the momentum of a car with a mass of 1,300 kg traveling at a speed of 28 m/s?
1 answer:
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Answer:
0.3619sec
Explanation:
Given that
Mass,m=148 g
Length,L=13 cm
Velocity,u'(0)=10 cm/s
We have to find the position u of the mass at any time t
We know that
Where
u(0)=0
Substitute the value
Substitute u'(0)=10
Substitute the values
Period =T = 2π/8.68
After half period
π/8.68 it returns to equilibruim
π/8.68 = 0.3619sec
Answer:
d = m× λ⇒ d = λ ×m×l / x
= 630× m × 3×3m/ 45×
m
= 1.26×m
Explanation:
the above calculation is based on Young’s double slit experiment where the two slits provide two coherent light sources which results either constructive interference or destructive interference when passing through a double slit.