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Nata [24]
3 years ago
14

What is the newtons 2nd law known as

Physics
2 answers:
nika2105 [10]3 years ago
7 0

Answer: The Second Law is also known as "The Law of Force and Acceleration." This relates to the observation that an object experiences an acceleration "a" when acted upon by a force "F" whereby these two are in linear relationship F = ma (with "m" the mass of the object)

Elanso [62]3 years ago
4 0
Newton's second law of motion pertains to the behavior of objects for which all existing forces are not balanced. The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object.
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A simple pendulum consisting of a bob of mass m attached to a string of length L swings with a period T. If the pendulum is take
Juli2301 [7.4K]

To solve this problem we will use the definition of the period in a simple pendulum, which warns that it is dependent on its length and gravity as follows:

T =2\pi \sqrt{\frac{L}{g}}

Here,

L = Length

g = Acceleration due to gravity

We can realize that 2 \pi is a constant so it is proportional to the square root of its length over its gravity,

T \propto \sqrt{\frac{L}{g}}

Since the body is in constant free fall, that is, a point where gravity tends to be zero:

g \rightarrow 0 \Rightarrow T \rightarrow \infty

The value of the period will tend to infinity. This indicates that the pendulum will no longer oscillate because both the pendulum and the point to which it is attached are in free fall.

5 0
3 years ago
Mary pushes a crate by applying force of 18 newtons. Unable to push it alone, she gets help from her friend, Anne. Together they
maw [93]
 <span>This problem is relatively simple, in order to solve this problem the only formula you need to know is the formula for friction, which is: 

Ff = UsN 

where Us is the coefficient of static friction and N is the normal force. 

In order to get the crate moving you must first apply enough force to overcome the static friction: 

Fapplied = Ff 

Since Fapplied = 43 Newtons: 

Fapplied = Ff = 43 = UsN 

and it was given that Us = 0.11, so all you have to do is isolate N by dividing both sides by 0.11 

43/0.11 = N = 390.9 which is approximately 391 or C. 3.9x10^2</span>
7 0
3 years ago
Read 2 more answers
A ball is projected upward at time t = 0.0 s, from a point on a roof 60 m above the ground. The ball rises, then falls until it
musickatia [10]
<span> y=y0 + vt +1/2gt^2
(solve for t here) cause you know y,y0,v,g
you will do quad formula here

then:
v=v0 +at solve for v
(remember the direction of the ball too (signs))

The main thing to remember here is that when the ball passes exactly (height) where it was launched it will travel the speed at which it was launched. *its almost like the ball was thrown in the downward direction. </span>
7 0
3 years ago
What object or class of objects makes up most of the solar system’s mass?
Vladimir [108]
Solar system is the gravitationally bound system that consists of the sun and the objects that orbit around it directly or indirectly. These objects includes the planets which orbit the sun directly an other small objects such as meteoroids, asteroids, satellites of the planets and numerous comets. The sun makes up most of the solar system' mass.
8 0
3 years ago
Read 2 more answers
You are asked to design a cylindrical steel rod 50.0 cm long, with a circular cross section, that will conduct 170.0 J/s from a
zepelin [54]

Answer:

You are asked to design a cylindrical steel rod 50.0 cm long, with a circular cross section, that will conduct 170.0 J/s from a furnace at 350.0 ∘C to a container of boiling water under 1 atmosphere.

Explanation:

Given Values:

L = 50 cm = 0.5 m

H = 170 j/s

To find the diameter of the rod, we have to find the area of the rod using the following formula.

Here Tc = 100.0° C

        k  = 50.2

       H = k × A × \frac{[T_{H -}T_{C} ] }{L}

Solving for A

       A  =  \frac{H * L }{k * [ T_{H}- T_{C} ] }

       A  = \frac{170 * 0.5}{50.2 * [ 350 - 100 ]}

       A  = \frac{85}{12550} = 6.77 ×10^{-3} m²

Now Area of cylinder is :

     A =  \frac{\pi }{4} d²

solving for d:

    d =  \sqrt{\frac{4 * 0.00677 }{\pi } }

    d  = 9.28 cm

5 0
3 years ago
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