Answer:
The electric current in the wire is 0.8 A
Explanation:
We solve this problem by applying the formula of the magnetic field generated at a distance by a long and straight conductor wire that carries electric current, as follows:
![B=\frac{2\pi*a }{u*I}](https://tex.z-dn.net/?f=B%3D%5Cfrac%7B2%5Cpi%2Aa%20%7D%7Bu%2AI%7D)
B= Magnetic field due to a straight and long wire that carries current
u= Free space permeability
I= Electrical current passing through the wire
a = Perpendicular distance from the wire to the point where the magnetic field is located
Magnetic Field Calculation
We cleared (I) of the formula (1):
Formula(2)
![B=0.2*10^{-5} T = 0.2*10^{-5} \frac{weber}{m^{2} }](https://tex.z-dn.net/?f=B%3D0.2%2A10%5E%7B-5%7D%20%20T%20%3D%200.2%2A10%5E%7B-5%7D%20%5Cfrac%7Bweber%7D%7Bm%5E%7B2%7D%20%7D)
a =8cm=0.08m
![u=4*\pi *10^{-7} \frac{Weber}{A*m}](https://tex.z-dn.net/?f=u%3D4%2A%5Cpi%20%2A10%5E%7B-7%7D%20%5Cfrac%7BWeber%7D%7BA%2Am%7D)
We replace the known information in the formula (2)
![I=\frac{2\pi*0.08*0.2*10^{-5} }{4\pi *10x^{-7} }](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B2%5Cpi%2A0.08%2A0.2%2A10%5E%7B-5%7D%20%20%7D%7B4%5Cpi%20%2A10x%5E%7B-7%7D%20%7D)
I=0.8 A
Answer: The electric current in the wire is 0.8 A
Answer:
The final position made with the vertical is 2.77 m.
Explanation:
Given;
initial velocity of the ball, V = 17 m/s
angle of projection, θ = 30⁰
time of motion, t = 1.3 s
The vertical component of the velocity is calculated as;
![V_y = Vsin \theta\\\\V_y = 17 \times sin(30)\\\\V_y = 8.5 \ m/s](https://tex.z-dn.net/?f=V_y%20%3D%20Vsin%20%5Ctheta%5C%5C%5C%5CV_y%20%3D%2017%20%5Ctimes%20sin%2830%29%5C%5C%5C%5CV_y%20%3D%208.5%20%5C%20m%2Fs)
The final position made with the vertical (Yf) after 1.3 seconds is calculated as;
![Y_f = V_yt - \frac{1}{2}g t^2\\\\Y_f = (8.5 \times 1.3 ) - (\frac{1}{2} \times 9.8 \times 1.3^2)\\\\Y_f = 11.05 \ - \ 8.281\\\\Y_f = 2.77 \ m](https://tex.z-dn.net/?f=Y_f%20%3D%20V_yt%20%20-%20%5Cfrac%7B1%7D%7B2%7Dg%20t%5E2%5C%5C%5C%5CY_f%20%3D%20%288.5%20%5Ctimes%201.3%20%29%20-%20%28%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%209.8%20%5Ctimes%201.3%5E2%29%5C%5C%5C%5CY_f%20%3D%2011.05%20%5C%20-%20%5C%208.281%5C%5C%5C%5CY_f%20%3D%202.77%20%5C%20m)
Therefore, the final position made with the vertical is 2.77 m.
The question is a little confusing. An electromagnetic wave is radiation. One doesn’t emit the other. Take another look at the question and write it again please.
The force is given by the product of mass and the acceleration thus the force is given
8480/32 is equal to 265 kg
Here, you can calculate it's potential energy with respect to ground.
We know, U = mgh
Here, m = 75 Kg
g = 9.8 m/s² [ constant value for earth system ]
h = 300 m
Substitute their values into the expression:
U = 75 × 9.8 × 300
U = 220500 J
In short, Your Final Answer would be 220,500 J
Hope this helps!