The density of an object is given by:
D = M/V
D = density, M = mass, V = volume
The volume of the cube V is given by:
V = s³
where s = side length
Make a substitution:
D = M/s³
Given values:
M = 20kg, s = 20×10⁻²m
Plug in and solve for D:
D = 20/(20×10⁻²)³
D = 2500kg/m³
Explanation:
We start by using the conservation law of energy:

or

Simplifying the above equation, we get

We can rewrite this as

Note that the expression inside the parenthesis is simply the acceleration due to gravity
so we can write

where
is the launch velocity.
The work done on the Puck by the applied force from the most positive to the most negative is c, b, a respectively.
According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.
F = ma

The force applied to an object increases with increases in the velocity of the object.
In the given diagram, the resultant velocity of the puck is calculated as follows;
Figure a:

Figure b:

Figure c:

Thus, the work done on the Puck by the applied force from the most positive to the most negative is c, b, a respectively.
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The volume of a gas will increase by ten times if the temperature is increased by ten times.
<h3>Relationship between the volume of a gas and temperature</h3>
The relationship between the volume of a gas and its temperature is explained in Charles' law of gases which states that:
- The volume of a fixed mass of gas is directly proportional to its temperature provided the pressure of the gas is kept constant.
This means that if the temperature of a gas is increased by any given factor, the volume increases by the same factor proportionally.
Therefore, if the volume of a gas will increase by ten times if the temperature is increased by ten times.
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