Answer:
Explanation:
Given:
The two rods could be approximated as a fins of infinite length.
TA = 75 0C θA = (TA - T∞) = 75 - 25 = 50 0C
TB = 55 0C θB = (TB - T∞) = 55 - 25 = 30 0C
Tb = 100 0C θb = (Tb - T∞) = (100 - 25) = 75 0C
KA = 200 W/m · K
T∞ = 25 0C
Solution:
The temperature distribution for the infinite fins are given by
θ/θb=e⁻mx
θA/θb= e-√(hp/A.kA) x1 ....................(1)
θB/θb = e-√(hp/A.kB) x1.......................(2)
Taking natural log on both sides we get,
Ln(θA/θb) = -√(hp/A.kA) x1 ...................(3)
Ln(θB/θb) = -√(hp/A.kB) x1 .....................(4)
Dicving (3) and (4) we get
[ Ln(θA/θb) /Ln(θB/θb)] = √(KB/KA)
[ Ln(50/75) /Ln(30/75)] = √(KB/200)
Answer:
FALSE
Explanation:
It is best practice to ALWAYS change the password of your router to something other than the default.
_____
Leaving the password as the default leaves the router open to exploitation by hostiles.
Answer:
And replacing in the Carnot efficiency we got:
Explanation:
For this case we can use the fact that the maximum thermal efficiency for a heat engine between two temperatures are given by the Carnot efficiency:
We have on this case after convert the temperatures in kelvin this:
And replacing in the Carnot efficiency we got:
And the maximum power output on this case would be defined as:
Where 
represent the heat associated to the deposit with higher temperature.
Answer:
the no. of activities supply in a cahin like in the figuration wise they supply the chain
