Answer:
41.5° C
Explanation:
Given data :
1025 steel
Temperature = 4°C
allowed joint space = 5.4 mm
length of rails = 11.9 m
<u>Determine the highest possible temperature </u>
coefficient of thermal expansion ( ∝ ) = 12.1 * 10^-6 /°C
Applying thermal strain ( Δl / l ) = ∝ * ΔT
( 5.4 * 10^-3 / 11.9 ) = 12.1 * 10^-6 * ( T2 - 4 )
∴ ( T2 - 4 ) = ( 5.4 * 10^-3 / 11.9 ) / 12.1 * 10^-6
hence : T2 = 41.5°C
Answer:
Explanation:
A confined aquifer is one that's impermeable and does not allow seepage's of water through it.
An unconfined aquifer is a body of water that has permeable membranes which allows passage of water through it.
There will be little or no transmission of water trough these bodies of water.
Answer:
View Image
Explanation:
Initialize your variable as a float or double since you're going to be using fractions in your answer.
User scanf() to get user input.
Print out the sum, product, quotient, and difference between the two numbers.
Answer:
Explanation:
cross sectional area A = 1.9 x 2.6 x 10⁻⁶ m²
= 4.94 x 10⁻⁶ m²
stress = 42 x 9.8 / 4.94 x 10⁻⁶
= 83.32 x 10⁶ N/m²
strain = .002902 / 2.7
= 1.075 x 10⁻³
Young's modulus = stress / strain
= 83.32 x 10⁶ / 1.075 x 10⁻³
= 77.5 x 10⁹ N/m²
Answer:
Explanation:
First we compute the characteristic length and the Biot number to see if the lumped parameter
analysis is applicable.
Since the Biot number is less than 0.1, we can use the lumped parameter analysis. In such an
analysis, the time to reach a certain temperature is given by the following
From the data in the problem we can compute the parameter, b, and then compute the time for
the ratio (T – T)/(Ti
– T)
