Question

The speed of propagation of the action potential (an electrical signal) in a nerve cell depends (inversely) on the diameter of the axon (nerve fiber). If the nerve cell connecting the spinal cord to your feet is 1.1 m long, and the nerve impulse speed is 18 m/s, how long does it take for the nerve signal to travel this distance?

Answer 1

Answer:

It will take 0.0611 sec for nerve signal to travel 1.1 m

Explanation:

We have given the nerve cell connecting the spinal card to feet is 1.1 m long

So length d = 1.1 m

And speed of the nerve impulse v = 18 m/sec

We have to find the time for nerve signal to travel that distance

Speed of the nerve signal is given by $v=\frac{d}{t}$

So $t=\frac{d}{v}=\frac{1.1}{18}=0.0611sec$

So it will take 0.0611 sec for nerve signal to travel 1.1 m