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LenaWriter [7]
3 years ago
11

670159 to the hundreds place

Mathematics
1 answer:
Rama09 [41]3 years ago
3 0
670200 is the answer
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Write an equation for the nth term of the geometric sequence below: (Equation NEEDS to be written as gn=7(5)^(n-1) or as gn=2/3(
andriy [413]

Answer:

You didn't give the geometric sequence in question.

But to find the nth term of a geometric sequence, use the formula

Sn = ar^(n - 1)

Where a is the first term of the sequence

r is the common ratio of the sequence.

Example: To find the nth term of the geometric sequence

1/2, 1/4, 1/8, 1/16, ...

Here, a = 1/2

r = 1/4 ÷ 1/2 = 1/8 ÷ 1/4 = 1/16 ÷ 1/8 = 1/2.

Sn = (1/2)(1/2)^( n - 1)

Apply this method to the sequence you were given, it will be helpful.

8 0
3 years ago
At the city museum, child admission is $5.30 and adult admission is $9.20 . On Monday, 166 tickets were sold for a total sales o
Sonbull [250]
C+a=166
a=166-c
5.3c+9.2a=1254.2
5.3c+9.2(166-c)=1254.2
5.3c+1527.2-9.2c=1254.2
5.3c-9.2c=1254.2-1527.2
-3.9c=-273
c=-273/-3.9
c=70
Hope this helps!

3 0
3 years ago
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
If 1 meter = 100cm then what is the relationship between m3 and cm3?
ddd [48]
If the 1m turns into 3m then he cm increases also by 3.The 3 meters would equal 300 cm.
8 0
3 years ago
Read 2 more answers
Rewrite each number sentence using numerals and symbols. Find the difference between 4 and 3 and then add 7 *
Zina [86]

Answer:

8

Step-by-step explanation:

4-3+7=8

8 0
2 years ago
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