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lapo4ka [179]
3 years ago
8

Argon has a completely filled p sublevel, giving it chemical stability. Potassium has one electron in the 4s sublevel and can ea

sily lose this electron, so it has a Argon has a completely filled p sublevel, giving it chemical stability. Potassium has one electron in the 4 s sublevel and can easily lose this electron, so it has a blank first ionization energy. Therefore, it blank the 4 s electron to achieve an blank electron configuration, giving it the added stability of the filled p sublevel. first ionization energy. Therefore, it Argon has a completely filled p sublevel, giving it chemical stability. Potassium has one electron in the 4 s sublevel and can easily lose this electron, so it has a blank first ionization energy. Therefore, it blank the 4 s electron to achieve an blank electron configuration, giving it the added stability of the filled p sublevel. the 4s electron to achieve an Argon has a completely filled p sublevel, giving it chemical stability. Potassium has one electron in the 4 s sublevel and can easily lose this electron, so it has a blank first ionization energy. Therefore, it blank the 4 s electron to achieve an blank electron configuration, giving it the added stability of the filled p sublevel. electron configuration, giving it the added stability of the filled p sublevel.
Chemistry
1 answer:
Stels [109]3 years ago
6 0

Potassium has one electron in the 4 s sublevel and can easily lose this electron, so it has a low first ionization energy.

Therefore, it lose the 4 s electron to achieve an Argon electron configuration, giving it the added stability of the filled p sublevel.

The ionization energy (Ei) is the minimum amount of energy required to remove the valence electron, when element lose electrons, oxidation number of element grows (oxidation process).

Potassium has lowe first ionization energy, so potassium easier remove one valence electron (4s¹).

Electron configuration of potassium is: ₁₉K 1s²2s²2p⁶3s²3p⁶4s¹.

Electron configuration of argon atom: ₁₈Ar 1s² 2s² 2p⁶ 3s² 3p⁶.

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Answer:

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ludmilkaskok [199]
The  RMS  of O2  at  17  degrees   is  calculated  as  follows

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6 0
3 years ago
Read 2 more answers
an aqeous solution of oxalic acid h2c2o4 was prepared by dissolving a 0.5842g of solute in enough water to make a 100 ml solutio
vampirchik [111]

The question is incomplete, here is the complete question:

An aqeous solution of oxalic acid was prepared by dissolving a 0.5842 g of solute in enough water to make a 100 ml solution a 10 ml aliquot of this solution was then transferred to a volumetric flask and diluted to a final volume of 250 ml. How many grams of oxalic acid are in 100. mL of the final solution?

<u>Answer:</u> The mass of oxalic acid in final solution is 0.0234 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}     ......(1)

Given mass of oxalic acid = 0.5842 g

Molar mass of oxalic acid = 90 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

\text{Molarity of oxalic acid solution}=\frac{0.5842\times 1000}{90\times 100}\\\\\text{Molarity of oxalic acid solution}=0.0649M

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated oxalic acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted oxalic acid solution

We are given:

M_1=0.0649M\\V_1=10mL\\M_2=?M\\V_2=250.0mL

Putting values in above equation, we get:

0.0649\times 10=M_2\times 250.0\\\\M_2=\frac{0.0649\times 10}{250}=0.0026M

Now, calculating the mass of glucose by using equation 1, we get:

Molarity of oxalic acid solution = 0.0026 M

Molar mass of oxalic acid = 90 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

0.0026=\frac{\text{Mass of oxalic acid solution}\times 1000}{90\times 100}\\\\\text{Mass of oxalic acid solution}=\frac{0.0026\times 90\times 100}{1000}=0.0234g

Hence, the mass of oxalic acid in final solution is 0.0234 grams

6 0
4 years ago
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