Hello!
Determine the mass of 5.20 moles of C6H12 (gram-formula mass = 84.2 grams/mole).
We have the following data:
m (mass) = ?
n (number of moles) = 5.20 moles
MM (Molar mass of C6H12) ≈ 84.2 g/mol
Now, let's find the mass, knowing that:
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The new volume : 21.85 ml
<h3>Further explanation</h3>Given
V1=25,0 ml
P1=725 mmHg
T1=298K is converted to
T2=273'K
P2=760 mmHg atm
Required
V2
Solution
Combined gas law :
Input the value :
V2=(P1.V1.T2)/(P2.T1)
V2=(725 x 25 ml x 273)/(760 x 298)
V2=21.85 ml
Answer:
for the given reaction is -99.4 J/K
Explanation:
Balanced reaction:
where represents standard entropy.
Plug in all the standard entropy values from available literature in the above equation:
So, for the given reaction is -99.4 J/K