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ahrayia [7]
2 years ago
9

What best describes the energy changes associated with evaporation and boiling

Chemistry
1 answer:
erik [133]2 years ago
4 0

Answer:The statement 'atoms gain energy during evaporation and boiling' BEST describes the energy changes associated with evaporation and boiling.

In a given substance (e.g., water), atoms gain energy when they obtain kinetic energy, i.e. when they gain movement.

Evaporation refers to the physical process where a liquid is converted to a gas (in this case, water).

These processes (evaporation and boiling) increase the kinetic energy of water molecules to the detriment of the potential energy.

In conclusion, the statement 'atoms gain energy during evaporation and boiling' BEST describes the energy changes associated with evaporation and boiling.

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The enthalpy of formation of water is –285.8 kJ/mol. What can be inferred from this statement?
LiRa [457]
A negative formation enthalpy means that the reaction is exothermic, or that heat is released during the process.
(C,)
4 0
4 years ago
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What is the freezing point in °C) of a 0.743 m
lesantik [10]

Answer:

-0.276 Degrees C

Explanation:

kf of water is 1.86

Freezing point depression= m x kf x i

i= ions present ( K+ Cl-) 1=2

1.86x2X.743= .276

Since its freezinf point depression the freezing point will lower

so

0-.276= -.276

7 0
3 years ago
A flexible container at an initial volume of 4.11 L contains 2.51 mol of gas. More gas is then added to the container until it r
Nitella [24]

Answer:

7.81 moles

Explanation:

To solve this problem, let us generate an expression involving volume and number of mole of the gas since the pressure and temperature of the gas are constant.

From ideal gas equation:

PV = nRT

Divide both side by P

V= nRT/P

Divide both side by n

V/n = RT/P

Since RT/P are constant, then:

V1/n1 = V2/n2

Data obtained from the question include:

V1 = 4.11

n1 = 2.51 moles

V2 = 16.9L

n2 =?

Using the above equation i.e V1/n1 = V2/n2, the final number of the gas can be obtained as illustrated below:

4.11/2.51 = 16.9/n2

Cross multiply to express in linear form

4.11 x n2 = 2.51 x 16.9

Divide both side by 4.11

n2 = (2.51 x 16.9) / 4.11

n2 = 10.32moles

Now, to obtain the number of mole of the gas added, we'll subtract the initial mole from the final mole i.e

n2 — n1

Number of mole added = n2 — n1

10.32 — 2.51 = 7.81 moles

Therefore, 7.81 moles of the gas was added to the container

3 0
3 years ago
Is light given off in small particles called photons
larisa86 [58]
Yep. it is.... sorry for making this a run on but it needs to be 20characters long
8 0
3 years ago
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If 30cm³ of 0.45 mol dm3 HCl reacted with NaOH, how many moles of HCl reacted?​
77julia77 [94]

Moles HCl reacted : 0.0135

<h3>Further explanation</h3>

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large {\boxed {\bold {M ~ = ~ \dfrac {n} {V}}}

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

So to find the number of moles can be expressed as

n = V x M

The volume of HCl 30 cm³=3.10⁻² dm³

Molarity of HCl = 0.45 mol/dm³

so moles HCl reacted :

\tt n=3.10^{-2}\times 0.45=0.0135

3 0
3 years ago
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