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RoseWind [281]
3 years ago
8

Oxidation Number of fe in fe3o4​

Chemistry
1 answer:
oee [108]3 years ago
4 0

Oxidation number of fe in the compound...,

Let the oxidation number of (Fe) be x

The oxidation number of oxygen(o) is (-2)

; 3x + 4(-2) = 0...where zero is the total charge on the compound(fe3o4)

; 3x = 8...then divide both sides by 3

Oxidation number of fe is( 2.67 )

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Type the correct answer in the box. Express your answer to two significant figures. An industrial vat contains 650 grams of soli
nikklg [1K]

88.98 %

The Balance Chemical Equation is as follow,

                                  2 HCl + Pb(NO₃)₂     →    2 HNO₃ + PbCl₂

According to equation,

          331.2 g (1 mole) Pb(NO₃)₂ produces  =  278.1 g (1 mole) PbCl₂

So,

                 870 g of Pb(NO₃)₂ will produce  =  X g of PbCl₂

Solving for X,

                     X  =  (870 g × 278.1 g) ÷ 331.2 g

                     X  =  730.5 g of PbCl₂

Therefore,

               Theoretical Yield =  730.5 g

Also as given,

                Actual Yield =  650 g

So using following formula for percentage yield,

                        %age Yield  =  (Actual Yield / Theoretical Yield) × 100

Putting values,

                        %age Yield  =  (650 g / 730.5 g) × 100

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Reika [66]
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4 0
3 years ago
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ivann1987 [24]

Answer:

C.

Explanation:

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So, the right choice is c.

A is wrong because 2 electrons of 3p are paired in the first orbital before filling every orbital.

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