13. Nt
14. St
15. St
16. At
17. Nt
Answer:
The pH changes by 2.0 if the [A-]/[HA] ratio of a base/weak acid mixture changes from 10/1 to 1/10.
Explanation:
To solve this problem we use the<em> Henderson-Hasselbach equation</em>:
Let's say we have a weak acid whose pKa is 7.0:
If the [A⁻]/[HA] ratio is 10/1, we're left with:
Now if the ratio is 1/10:
The difference in pH from one case to the other is (8.0-6.0) 2.0.
<em>So the pH changes by 2.0</em> if the [A-]/[HA] ratio of a base/weak acid mixture changes from 10/1 to 1/10.
<u>Keep in mind that no matter the value of pKa, the answer to this question will be the same.</u>
Answer:
if i had to guess it would be D
Explanation:
Sorry if im wrong, but i wouldnt have any liquid on atleast one of them so i can compare and contrast the other coins to the regular 1p coins
Answer:
the answer would be ;B compare the volumes of the three cylinders
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